After he selects the Push transition, He should select from Left option from the Effect Options drop-down menu.
<h3>What is push transition in PowerPoint?</h3>
The Push Transition Effect is known to be a function in a PowerPoint that helps to pushes one slide to show the other.
Note that when this is applied to any presentation, it moves the current slide upwards to reveal the next slide and so on. A person can add use this kind of effect to present a scrolling effect to one's PowerPoint work.
Learn more about presentation from
brainly.com/question/24653274
Video editors are used to edit videos making them more visually pleasing in quality and appearance. They are very popular nowadays when people are fond of taking videos and uploading them to social networking sites. Examples are Adobe Premier PRo, Sony Vegas Movie studio and Lightworks.
I think it would be B. The average monthly sales for the big toy company because its giving data over history
Answer:
cables, towers, and underground tubes
Explanation:
Its certainly the above one, and through this internet service is being provided. So internet service is self-understood, and what ISP firstly provides are cables, underground tubes, and the towers. And it is only these all through which the ISP provides internet service. And remember we are in this question dealing with the infrastructure and not the services or products. Hence, phone service, websites, and files, as well as the emails, search engines, and the videos, are not the solution here as they are not the infrastructure. And ISPs never provide the computers, ethernet cables or keyboards.
Hence, the correct answer is as mentioned in the answer section.
Answer:
0.8488
Explanation:
Let E =error found by test 1
Let F=error found by test 2
Let G=error found by test 3
Let H=error found by test 4
Let I= error found by test 5
Given P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5
therefore P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5
Tests are independent P(not E & not F ¬ G & not H & not I=P(notE)*P(notF)*P(notG)*P (notH)*P (not I) =0.9*0.8*0.7*0.6*0.5 =0.1512
P(found by at least one test)= 1- P(not found by any test)=1-P(not E& not F & not G & not H & not I ) = 1-0.1512 = 0.8488