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Alex777 [14]
3 years ago
11

I need help ASAP!!! Please tell me the answer Congruent Triangle Proof

Mathematics
2 answers:
LenaWriter [7]3 years ago
7 0

Answer:

Step-by-step explanation:

In Δ MNP,

∠NMQ ≅ ∠NPQ

⇒ NM = NP - ------> (I)     {Sides opposite to equal angles are equal}

In ΔMNQ & ΔPNQ,

∠MNQ  ≅ ∠PNQ             {NQ is angle bisector}

NM  = NP                     {from (I)}

∠NMQ ≅ ∠NPQ           {Given}

ΔMNQ ≅ ΔPNQ          -  Angle Side Angle  {ASA congruent}

Nata [24]3 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

If 2 angles and the included side of one triangle are congruent to 2 angles and the included side of another triangle, then the triangles are congruent.

NQ is an angle bisector then ∠ MNQ = ∠ PNQ

∠ M = ∠ N , so the triangle is isosceles with 2 equal legs, then

MN = PN

----------------------------------------------

∠ MNQ = ∠ PNQ

MN = PN ( included sides between the 2 angles )

∠ M = ∠ N

Δ MNQ ≅ Δ PNQ by the ASA postulate

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Answer:

Suppose we have a random number A.

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This means that (1/A) is the multiplicative inverse of A.

Where we need to have A ≠ 0, because we can not divide by 0.

Now we want to find the multiplicative inverse of the numbers:

2: Here the inverse is (1/2) = 0.5

1/5:  Here the inverse is  (1/(1/5)) = (5/1) = 5

-4: Herre the inverse is  (1/(-4)) = -(1/4) = -0.25

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There are 50 deer in a particular
olchik [2.2K]

answered

There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents

the number of deer y in that forest after x months? Round to the nearest thousandth.

1

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dribeiro

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697 answers

561.4K people helped

Answer:

The expression that represents the number of deer in the forest is

y(x) = 50*(1.013)^x

Step-by-step explanation:

Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:

y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625

y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258

y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898

This keeps going as the time goes on, so we can model this growth with the equation:

y(x) = 50*(1 - 0.15/12)^(x)

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