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Grace [21]
3 years ago
7

The graph below shows Roy's distance from his office (y), in miles, after a certain amount of time (x), in minutes: Graph titled

Roys Distance Vs Time shows 0 to 10 on x and y axes at increments of 1.The label on x axis is time in minutes and that on y axis is Distance from Office in miles. Lines are joined at the ordered pairs 0, 0 and 1, 1 and 2, 2 and 3, 3 and 4, 4 and 5, 4 and 6, 4 and 7, 4.5 and 7.5, 5 and 8, 6. Four students described Roy's motion, as shown in the table below: Student Description Peter He drives a car at a constant speed for 4 minutes, then stops at a crossing for 6 minutes, and finally drives at a variable speed for the next 2 minutes. Shane He drives a car at a constant speed for 4 minutes, then stops at a crossing for 2 minutes, and finally drives at a variable speed for the next 8 minutes. Jamie He drives a car at a constant speed for 4 minutes, then stops at a crossing for 6 minutes, and finally drives at a variable speed for the next 8 minutes. Felix He drives a car at a constant speed for 4 minutes, then stops at a crossing for 2 minutes, and finally drives at a variable speed for the next 2 minutes. Which student most accurately described Roy's motion? Peter Shane Jamie Felix

Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0

Answer:

Felix

Step-by-step explanation:

The graph contains 3 segments,

first one is for the first 4minutes,

second one is for the next 2 minutes (standing still)

third one is for the last 2 minutes.

Only Felix has it right, the other students use absolute time in their statements, in stead of the difference between start and end. (e.g., from 4 to 6 is 2 minutes).

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Purchased a living room set for $3,800 at 11% add on interest for 3 years , whats the nearest tenth of a percent for the loan de
ELEN [110]

Answer:

The loan amount after 3 years is $ 5,196.88

Step-by-step explanation:

Given as :

The principal amount for room loan = $ 3,800

The rate of interest applied = 11% compounded annually

The time period of loan = 3 years

Let The Total loan amount = $ A

Now,<u> From Compounded method :</u>

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

or, A = $ 3,800 × (1+\dfrac{\textrm 11}{100})^{\textrm 3}

or, A = $ 3,800 × (1.11)³

or,  A = $ 3,800 × 1.3676

∴ A = $ 5,196.88

So, Amount after 3 years = A = $ 5,196.88

Hence The loan amount after 3 years is $ 5,196.88 Answer

3 0
3 years ago
Find the probability of having 2,3, or 4 successes in five trials of a binomial experiment in which the probability of success i
DiKsa [7]

0.45033504848

Explanation:

The binomial formula is given by
<span>nCk⋅<span>ρk</span><span><span>(1−ρ)</span><span>n−k</span></span></span> thus the result for x would be

<span>p<span>(x=2)</span>=<span>(<span><span>5!</span><span><span>(5−2!)</span>2!</span></span>)</span><span><span>(.4)</span>2</span><span><span>(1−.4)</span><span>5−2</span></span>=0.3456</span>

<span>p<span>(x=3)</span>=<span>(<span><span>5!</span><span><span>(5−3!)</span>3!</span></span>)</span><span><span>(.4)</span>3</span><span><span>(1−.4)</span><span>5−3</span></span>=0.13824</span>

<span>p<span>(x=4)</span>=<span>(<span><span>5!</span><span><span>(5−4!)</span>4!</span></span>)</span><span><span>(.4)</span>4</span><span><span>(1−.4)</span><span>5−4</span></span>=0.027648</span>

<span><span>p<span>(a∪b∪c)</span>=p<span>(a)</span>+p<span>(b)</span>+p<span>(c)</span>−p<span>(a)</span>⋅p<span>(b)</span>−p<span>(a)</span>⋅p<span>(c)</span>−p<span>(b)</span>⋅p<span>(c)</span></span><span>=.3456+.13824+.027648−.047775744−.0095551488−0.00382205952</span></span>

<span>p<span>(a∪b∪c)</span>=<span>0.45033504848</span></span>

6 0
3 years ago
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faltersainse [42]
B. 011.31 the means that the area
8 0
3 years ago
100%
sweet [91]

Answer:

17 inches

Step-by-step explanation:

it's 17 because x² = 15² + 8²

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3 0
3 years ago
PLEASE HELP ME JUST NEED TO ANSWER A OR B OR BOTH IF U WANT
Solnce55 [7]

Answer: Part A - 113°

Step-by-step explanation:

A. 6x-5 = 5x+7 -> x = 12

6x-5 -> 6(12)-5 = 72-5 = 67

180-67 = 113

6 0
3 years ago
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