Answer:
40 mph
Step-by-step explanation:
at least I won't crash in one second, and that's not that slow.
Answer:
= 105(x+2)/33-x
Step-by-step explanation:
Given the expression
[3(x+2)*10*7]÷70 - 2(x+2)
= 3(x+2)*70÷70 - 2(x+2)
= 210(x+2)/70-2x-4
= 210(x+2)/66-2x
= 210(x+2)/2(33-x)
= 105(x+2)/33-x
Answer:
N = -3.36
Step-by-step explanation:
5.6 x N= 2.24
-5.6 -5.6
N= -3.36
Answer:
A line segment is <u><em>always</em></u> similar to another line segment, because we can <u><em>always</em></u> map one into the other using only dilation a and rigid transformations
Step-by-step explanation:
we know that
A<u><em> dilation</em></u> is a Non-Rigid Transformations that change the structure of our original object. For example, it can make our object bigger or smaller using scaling.
The dilation produce similar figures
In this case, it would be lengthening or shortening a line. We can dilate any line to get it to any desired length we want.
A <u><em>rigid transformation</em></u>, is a transformation that preserves distance and angles, it does not change the size or shape of the figure. Reflections, translations, rotations, and combinations of these three transformations are rigid transformations.
so
If we have two line segments XY and WZ, then it is possible to use dilation and rigid transformations to map line segment XY to line segment WZ.
The first segment XY would map to the second segment WZ
therefore
A line segment is <u><em>always</em></u> similar to another line segment, because we can <u><em>always</em></u> map one into the other using only dilation a and rigid transformations
Answer:
It would roll in this direction.

Step-by-step explanation:
It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.
Since

For this case, the gradient of your function would be

And -1 times the gradient of your function would be

Then, at

So it would go towards

The magnitud of that vector is

and to conclude it would roll in this direction.
