Assuming the length is y and the width is x
Perimeter = y + y + x + x
= 2y +2x
= 2 (y + x)
if the is 8 and the perimeter is 108
108 = 2 (y +8)
108/2 = y+8
54 = y +8
54 - 8 = y
46 = y
Length = 46 inches
Answer:
x = 1.8
Step-by-step explanation:
2 ( 4x-3) - 8 = 4-2x
Distribute
8x -6 -8 = 4- 2x
Combine like terms
8x - 14 = 4 - 2x
Add 2x to each side
8x - 14 +2x = 4-2x+2x
10x-14 = 4
Add 14 to each side
10x-14+14 = 4+14
10x = 18
Divide by 10
10x/10 = 18/10
x = 1.8
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
To find the z-score for a weight of 196 oz., use

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
No. Arkansas is between 33° and 36.5° latitude