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damaskus [11]
2 years ago
7

Solve for e.9e + 4 = -5e + 14 + 13e

Mathematics
2 answers:
sladkih [1.3K]2 years ago
5 0

Answer:

10.

Step-by-step explanation:

9e + 4 = -5e + 14 + 13e

9e + 5e - 13e = 14 - 4

e = 10

lora16 [44]2 years ago
5 0

Answer:

10

Step-by-step explanation:

9e + 4 = -5e + 14 + 13e

9e + 4 = 8e + 14

9e - 8e = -4 + 14

e = 10

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98 POINTS!!!!!!!!!!!!!!!!!!
Tanzania [10]

Answer:

a = 13 and b = 12-5i

Step-by-step explanation:

We need a common denominator

3+2i         5-i

---------- + ---------

3-2i          2+3i

(3+2i) (2+3i)         (5-i)(3-2i)

------------------ + --------------------

(3-2i) (2+3i)          (2+3i) (3-2i)

Foil the numerators

6 +4i+9i+6i^2 +15-3i-10i+2i^2        

------------------ --------------------

         (2+3i) (3-2i)

Combine like terms

21 +8i^2          

------------------

(2+3i) (3-2i)

We know that i^2 = -1

21 +8(-1)        

------------------

(2+3i) (3-2i)

21 -8        

------------------

(2+3i) (3-2i)

13        

------------------

(2+3i) (3-2i)

Foil the denominator

13

---------------

6 +9i -4i -6i^2

Combine like terms

13

----------------

6+ 5i -6(-1)

13

----------

12 +5i

We know have

13

-------------

12 + 5i

Multiply by the conjugate

13               ( 12-5i)

------------- * -------------

12 + 5i         12 -5i

13 (12-5i)

--------------

144 +25

13(12-5i)

-------------

169

12-5i

------------

13

The parentheses are (12-5i)/13

We need the reciprocal to make the equation become 1

which is 13/ 12-5i

a = 13 and b = 12-5i

5 0
3 years ago
Read 2 more answers
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