Modular Arithmetic
a is congruent to bmod (n)
Note that b is remainder after a goes into n
since n|a-b
consider 5z={0,1,2,3,4}
12=2mod5 since 5|12-2 => 5|10 => 2 which is remainder of 5 into 12 two times
Answer:
Step-by-step explanation:
We have a circle that is split in three sections, two of which we know and we are asked to find the third missing section.
For the circle, we know that 4/5 and 1/10 is fit. Now we need the last one, to solve, we need to get the same denominator and see how much is missing.
Since 1/10 is our highest denominator, let's change 4/5 to have 10 as a denominator. Which would be through multiplying 5 to get 10.
What times 5 equals 10?
2
Now multiply both numerator and denominator by 2 to get our portion.
Now we have the same denominator, let's add our two fractions and see how much we have left.
8/10 + 1/10
9/10
We have 1/10 missing, therefore 1/10 is the answer.
The simplified expression is 8a8b.
You would need to add 22 to 38 then divide that answer by 5 to get x