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3 years ago

Write an equation of the form y=kx for the relationship shown in the graph.

Mathematics

1 answer:

jekas [21]3 years ago

8 0

Answer:

28 = 8k

Step-by-step explanation:

(x,y)

so (8,28)

y = kx is a direct proportional formula.

28 = 8k

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6tf & 10ft radius what the answer

guapka [62]

All you have to do is 3.14×6×10 Which is 188.4

4 0

3 years ago

4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

6 0

3 years ago

What is 8/12 in simplest form

Pani-rosa [81]

8/12 in simplest form is 2/3.

5 0

3 years ago

Pizza Time has collected data about customer pizza topping preferences. They have calculated that P(pepperoni) = 0.7, P(olives)

inn [45]

We are given with the probabilities P(pepperoni) = 0.7, P(olives) = 0.6, and P(pepperoni or <span>olives) = 0.8. in this case, we are asked to determine P(pepperoni and olives) that is determined from P(pepperoni) + P(olives) - P(pepperoni or olives) equal then to 0.7 + 0.6 - 0.8 equal to 0.5</span>

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3 years ago

A line has a slope of –3 and a y-intercept of (0, –1). What is the equation of the line that is parallel to the given line and p

givi [52]

Well, the first line has a slope of -3, and runs through 0, -1.

a line parallel to that one, will have the same exact slope of -3.

now, we know about this other parallel line that it runs through -3,1, and of course, since is parallel, it has a slope of -3

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1\\
&&(~ -3 &,& 1~)
\end{array}
\\\\\\
% slope = m
slope = m\implies -3
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=-3[x-(-3)]
\\\\\\
y-1=-3(x+3)
\implies 
y-1=-3x-9\implies y=-3x-8$

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3 years ago