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My name is Ann [436]
3 years ago
13

the length of the rectangle is twice its width. write and solve a system of linear equations to find the length L and width W of

the rectangle... The perimeter is 36 ft​
Mathematics
1 answer:
xz_007 [3.2K]3 years ago
5 0

Answer:

2 ( m + 2 m)  = 36 is the required linear equation

Length of the rectangle is 12 ft and width =  6 ft

Step-by-step explanation:

Let the width of the rectangle = m ft.

So, the length of the rectangle = 2m  ft.

Perimeter  of rectangle = 36 ft

Now, PERIMETER OF THE RECTANGLE = 2(LENGTH + WIDTH)

⇒2 ( m + 2m)  = 36

or, 2 x 3m  = 36

⇒ 6m  = 36  , or m  = 36/6

⇒ m  =6 ft

So, the Width of the rectangle;  =  m = 6 ft

and the Length of the rectangle  = 2 m  = 2 x 6 =  12 ft.

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Kristin wants to wrap a ribbon around the perimeter of a rectangle. The length is five less than twice the width. The perimeter
romanna [79]

The length of the rectangle is 51 inches while the width of the rectangle is 28 inches.

Since Kristin wants to wrap a ribbon around the perimeter of a rectangle, the perimeter of a rectangle P = 2(L + W) where L = length of rectangle and W = width of rectangle.

Given that the perimeter of the rectangle, P = 56 inches and the length of the rectangle, L is five less than twice the width of the rectangle, W we have that

L = 2W - 5

Substituting L into P, we have

P = 2(2W - 5 + W)

P = 2(W - 5)

Since P = 56, we have

2(W - 5) = 56

~Dividing both sides by 2, we have

W - 5 = 56/2

W - 5 = 23

Adding 5 to both sides, we have

W = 23 + 5

W = 28 inches

Substituting W into L, we have

L = 2W - 5

L = 2(28) - 5

L = 56 - 5

L = 51 inches

So, the length of the rectangle is 51 inches while the width of the rectangle is 28 inches.

Learn more about perimeter of a rectangle here:

brainly.com/question/16715918

5 0
2 years ago
Teo has a combination of quarters, loonies, and toonies in his pocket.
finlep [7]

Answer:

343

Step-by-step explanation:

There are quarters(25¢), loonies ($1), and toonies ($2)

And total number of coins is 9

If loonies ($1), and toonies ($2) are one, then quarters(25¢) is 7

If quarters(25¢), and toonies ($2) are one, then loonies ($1)is 7

If loonies ($1), and quarters(25¢) are one, then toonies ($2) is 7

So possible number number of combination for an item that cost between $10 and $12 is

= 1^3 * 1^3 * 7^3

= 343

hope this helps, stay safe :)

3 0
3 years ago
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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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