You need more information than that to solve for x and y. However, it is possible for you to graph the equation and see what all the possible values for x and y can be. A possible coordinate can be x=3 and y=3.
Answer:
C = 62.8 m
Step-by-step explanation:
The circumference formula is C = πd.
Here d = 20 m. Therefore, the circumference of this circle is C = (20 m)π.
To the nearest 10th, we round off C = (20 m)(3.14159) = C = 62.8 m
Answer:
ok it is there is no question lol
Step-by-step explanation:
Answer:
9.6 square inches.
Step-by-step explanation:
We are given that ΔBAC is similar to ΔEDF, and that the area of ΔBAC is 15 inches. And we want to determine the area of ΔDEF.
First, find the scale factor <em>k</em> from ΔBAC to ΔDEF:

Solve for the scale factor <em>k: </em>
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Recall that to scale areas, we square the scale factor.
In other words, since the scale factor for sides from ΔBAC to ΔDEF is 4/5, the scale factor for its area will be (4/5)² or 16/25.
Hence, the area of ΔEDF is:

In conclusion, the area of ΔEDF is 9.6 square inches.
Answer:
This is an isosceles right triangle, then we have
2 x u^2 = [6sqrt(2)]^2
<=> 2 x u^2 = 72
<=> u^2 = 36
<=> u = 6
Hope this helps!
:)