Answer:
6.9%.
Step-by-step explanation:
Given that a university class has 26 students: 12 are art majors, 9 are history majors, 5 and are nursing majors, and the professor is planning to select two of the students for a demonstration, where the first student will be selected at random, and then the second student will be selected at random from the remaining students, to determine what is the probability that the first student selected is a history major and the second student is a nursing major the following calculations must be performed:
26 = 100
9 = X
9 x 100/26 = X
900/26 = X
34.61 = X
25 = 100
5 = X
500/25 = X
20 = X
0.2 x 0.3461 = X
0.069 = X
Thus, the probability that the first student selected is a history major and the second student is a nursing major is 6.9%.
Answer:
-8
Step-by-step explanation:
what do you think, when you look at the examples given in the problem definition ?
don't you see the pattern, that f(x) = x+2 ?
f(1) = 1+2 = 3
f(2) = 2+2 = 4
f(3) = 3+2 = 5
so, if we follow this assumption, then
f(-10) = -10 + 2 = -8
9514 1404 393
Answer:
C, A, A
Step-by-step explanation:
In general, you ...
- identify the coefficients of one of the variables
- swap them, and negate one of them
- multiply the corresponding equations by the "adjusted" coefficients.
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In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:
multiply equation 2 by -4 . . . (eliminates x)
Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:
multiply equation 1 by 3 . . . (eliminates y)
These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.
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The other problems are worked in a similar fashion.
You have to use the distance formula. sqrt((x2-x1)^2+(y2-y1)^2) So sqrt((4+3)^2+(-5-2)^2). sqrt(49+49). Sqrt(98). 9.89
Answer:
32 cm by 18 cm
16 cm by 36 cm,
48 cm by 12 cm
24 cm by 24 cm
Step-by-step explanation:
<u><em>The complete question is</em></u>
A boy wants to build rectangular cages. He wants all the sides on the base of his cages to beat least 10 cm long.he also wants the base area to equal 576 cm2. The boy needs help to find all the possible lengths and widths for the base of the cages. He used only whole centimeters, with no fractional parts.what are all the possible dimensions for the rectangular base?
we know that
The number 576 decompose in prime factors is the same that write
To find out possible side lengths, multiply different combinations of these prime numbers together (make sure each pair adds up to 10)
3x3=9cm 2x2x2x2x2x2= 64cm ----> is not a combination (one side is not greater than 10)
3x3x2= 18cm 2x2x2x2x2= 32cm
3x3x2x2= 36cm 2x2x2x2= 16cm
3x2x2= 12cm 3x2x2x2x2= 48cm
3x2x2x2= 24cm 3x2x2x2= 24cm
therefore
32 cm by 18 cm
16 cm by 36 cm,
48 cm by 12 cm
24 cm by 24 cm