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lapo4ka [179]
3 years ago
5

Find the value of x 18 20 x

Mathematics
1 answer:
sesenic [268]3 years ago
4 0
21 420 69 thank you very much
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Explain how finding 7x20 is similar to finding 7 x 2,000. Then find each product
Sphinxa [80]
7×20 and 7×2000 are similar. The amount of zeros are the dependent factor.

7×20= 140
7×2000= 14000

The base equation is 7×2=14
Any additions of zeroes in this formula will be added at the end result.

Ex.
7×2=14
7×20=140
7×200=1400
70×200=14000
700×200=140000
5 0
3 years ago
Last year the population of Spoon Forks grew from 1250 to 1300. If the population of the town grows by the same percent this yea
Reptile [31]

Answer:

1352

Step-by-step explanation:

Firstly, we get the percentage growth last year. This is calculated as:

(1300-1250)/1250 * 100

= 4%

Now, we are assuming the growth rate is constant. So let’s calculate a 4% growth rate for this year. That would be:

4/100 * 1,300 = 52

The population this year would thus be 1300 + 52 = 1352

4 0
4 years ago
To get from one town to another, Jack must travel 7 miles east and 24 miles south. What is the direct distance between the two t
Step2247 [10]
The 7 miles and 24 miles make up two "legs" of a right triangle.
The third side (or hypotenuse) is the distance between the towns.
distance^2 = 7^2 + 24^2
distance^2 = 49 + 576
distance^2 = 625
distance = square root of 625 or 25
3 0
4 years ago
Well when you do a problem and it's multiplication and you have to us your math skills and then when you get it wrong don't that
masha68 [24]
Not necessarily. You could have done your multiplication wrong. Or in some cases, yes, you could have to use another skill. For example, you can't solve an optimization problem with addition, you need some calculus skills under your belt.
8 0
3 years ago
If z^2+1/z^2=11 , find the value of z^3-1/z^3,using only the positive value of z-1/z
vredina [299]
Hello,

Let's assume

t=z- \dfrac{1}{z} \\\\

t^2=z^2-2+ \dfrac{1}{z^2}= 11-2=9==\ \textgreater \ t=3\\\\

t^3=z^3-3z^2* \dfrac{1}{z} +3z* \dfrac{1}{z^2} - \dfrac{1}{z^3} \\\\
=z^3 - \dfrac{1}{z^3} -3(z-\dfrac{1}{z})\\\\
z^3 - \dfrac{1}{z^3}=t^3+3t=3^3+9=27+9=36



7 0
3 years ago
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