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3 years ago

Can someone please help me it's urgent! Classify triangle ABC. Justify your classification.

Mathematics

1 answer:

Solnce55 [7]3 years ago

3 0

Answer:

It's an equilateral triangle because it has 3 equal sides

Step-by-step explanation:

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Mark set his watch 12.96 seconds behind, and it falls behind another 1.97 seconds every day. How many days has it been since Mar

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Answer:13 to 14

Step-by-step explanation:

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3 years ago

(13+2) + (13-2) please help....<br> Asap<br> Ty

just olya [345]

Answer:

$= > (13 + 2)(13 - 2)$

$= > 15 \times 11$

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2 years ago

Oliwia made a scale copy of the following triangle she used a scale factor greater than 1 whats the height

Mariana [72]

Answer:

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4 years ago

(12a^(2) - 3)/(2)*(2a + 1)^(-2)*((6)/((2a + 1)))^(-1)

Elena L [17]

Answer:

$\frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\$

Step-by-step explanation:

$\frac{(12a^2-3)}{2*(2a+1)^{-2}}*\frac{6}{(2a+1)^{-1} }\\ = \frac{(12a^2-3)}{2 * \frac{1}{(2a+1)^{2} }} * \frac{6}{\frac{1}{2a+1} }\\ =\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}\\=\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}$

$= \frac{(12a^2-3)(4a^{2} + 1 + 2 (2a)(1))}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{1} * \frac{3}{2a+1}\\= \frac{3(12a^2-3)(4a^{2} + 1 + 4a)} {2a+1}\\\\= \frac{3(12a^2(4a^{2} + 1 + 4a) - 3 (4a^{2}+1+4a)} {2a+1}\\= \frac{3(48a^{4}+12a^{2}+48a^{3} - 12a^{2} -12 - 4a)} {2a+1}\\= \frac{144a^{4}+36a^{2}+144a^{3} - 36a^{2} - 36 - 12a)} {2a+1}$

$= \frac{144a^{4}+36a^{2}+144a^{3} - 36a^{2} - 36 - 12a} {2a+1}\\= \frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\$

6 0

4 years ago

Find the equation of the line that is perpendicular to y=3y-x=7 and contains the point (2,-1).

a_sh-v [17]

First you want to get it into standard form. which would mean you get the x of the side of the y and divide everything by the y's coefficient in this case 3.

3y-x=a

3y=x+a

y=1/3x+a

Now your going to want to turn this into a perpendicular li e which means you flip the coefficient and make it negitive

y=-3x+a

then we fill in the points.

-1=-3(2)+a

Solve

-1=-6+a

-1+6=a

5=a

Now put it in standard form.

y=-3x+5

3 0

4 years ago