Answer:
44% cahnce
Step-by-step explanation:
To solve this, add up all the customers. Then, divide the amount of debit card customers, by the total amount of customers. This will give you percentage of people who paid in debit, which is also the probability:
20+26+13
=
59
This is the amount of customers. Now we divide:
26/59
=
0.4406
Remember that to create percentage, you must multiply the decimal by 100:
0.4406*100
=
44.06%
The .06 is so small that it doesnt need to be kept in this percentage:
44%
So this is you answer!
Hope it helps! :)
Answer:
$900
Step-by-step explanation:
If the $810 is the price after 10% discount that means
$810 is 90% of the original price
So we divide 810 / 90% or 810 / 0.9
to get $900 as final price
4480 dollars is what the 3 percent interest for 4 years
(x^2+4)^2 + 32 = 12x^2 + 48 .... a = x^2 + 4
<span>(x^2 + 4)^2 + 32 = 12(x^2 + 4) </span>
<span>a^2 + 32 = 12a </span>
<span>a^2 - 12a + 32 = 0 </span>
<span>(a - 8)(a - 4) = 0 </span>
<span>a = 8 and a = 4 </span>
<span>for a = 8 ... 8 = x^2 + 4 ... x^2 = 4 ... x = +/- 2 </span>
<span>for a = 4 ... 4 = x^2 + 4 ... x^2 = 0 ... x = 0 </span>
<span>x = -2, 0, +2 so your answer is going to be e
</span>
Answer:

Step-by-step explanation:
S = (x1,y1) = (0,-5)
T = (x2,y2) = (-8,-7)
<u>Using distance formula to find the length of ST</u>.
![|ST|= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\|ST| = \sqrt{(-8-0)^2+(-7-(-5))^2} \\\\|ST| = \sqrt{(-8)^2+(-7+5)^2} \\\\|ST| = \sqrt{64+(2)^2}\\\\|ST| = \sqrt{64+4} \\\\|ST| = \sqrt{68} \\\\|ST| = 8.2 \ units\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%7CST%7C%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%20%5C%5C%5C%5C%7CST%7C%20%3D%20%5Csqrt%7B%28-8-0%29%5E2%2B%28-7-%28-5%29%29%5E2%7D%20%5C%5C%5C%5C%7CST%7C%20%3D%20%5Csqrt%7B%28-8%29%5E2%2B%28-7%2B5%29%5E2%7D%20%5C%5C%5C%5C%7CST%7C%20%3D%20%5Csqrt%7B64%2B%282%29%5E2%7D%5C%5C%5C%5C%7CST%7C%20%3D%20%5Csqrt%7B64%2B4%7D%20%5C%5C%5C%5C%7CST%7C%20%3D%20%5Csqrt%7B68%7D%20%5C%5C%5C%5C%7CST%7C%20%3D%208.2%20%5C%20units%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)