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Nutka1998 [239]
3 years ago
9

Help me pls i need help asap​

Mathematics
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer:

no babe

Step-by-step explanation:

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Simplify 0, -6 please :(
snow_tiger [21]

Answer:

You cant simplify it??????

Step-by-step explanation:

3 0
3 years ago
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The map shows a typical flight path between Seattle and London. Why does the path go over the Arctic? A) It is the shortest path
Triss [41]
The answer to the given question above would be option A. Based on the given map shown above which is a typical flight path between Seattle and London, the reason why the path goes over the Arctic is that, it is the shortest path. Hope this answers your question.
4 0
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What is the product,in square of the width (x = 18x) and the height (y) of the prism??
a_sh-v [17]
I think the answer to (Y) may be 40 cubic units
6 0
3 years ago
A dog won a race at the local fair by running 3 and one fourth miles in exactly 2 hours. At this constant​ rate, how long does i
Novosadov [1.4K]

Answer:

\frac{4}{5} hour

Step-by-step explanation:

Let x represent time taken by dog to run the 1 and three tenths ​-mile state fair​ race.

We have been given that a dog won a race at the local fair by running 3 and one fourth miles in exactly 2 hours.

We will use proportions to solve our given problem as:

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

We will equate both speeds as:

\frac{1\frac{3}{10}}{x}=\frac{3\frac{1}{4}}{2}

\frac{\frac{13}{10}}{x}=\frac{\frac{13}{4}}{2}

\frac{13}{10\cdot x}=\frac{13}{4\cdot 2}

Cross multiply:

13\cdot 10\cdot x=13\cdot 4\cdot 2

10\cdot x=4\cdot 2

\frac{10\cdot x}{10}=\frac{4\cdot 2}{10}

Therefore, it will take \frac{4}{5} hour to complete 1\frac{3}{10} mile state fair​ race.

7 0
3 years ago
A regular square pyramid just fits inside a cube (the base of the pyramid is congruent to a face of the cube and
zlopas [31]
Volume of reg sq. pyramid = vp
vp = 1/3×s^2×h, where s = side and h = height
Volume of cone = vc =1/3×h×pi×r^2
Now we know that h is the same for both, and the cones diameter = s of square base, so radius (r) = 1/2 s
so now vc = 1/3×h×pi×(1/2s)^2
let's remove the same items for both vc and vp
so 1/3 and h
now let's plug an arbitrary number into each:
vc = pi (10/2)^2 = 3.14×25 = 78.54
vp = s^2 = 10^2 = 100
So any square pyramid has slightly more volume than the cone
4 0
3 years ago
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