Step-by-step explanation:
50
Answer:


Then we can find the probability of interest with this difference:
And using the normal standard distribution or excel we got:
So then the probability that the sample mean would differ from the true mean by less than 28 dollars from the sample of 55 is approximately 0.390
Step-by-step explanation:
We define the variable of interest as the per capita income and we know the following properties for this variable:
and
We want to find this probability:
We select a sample size of n=55 and we define the z score formula given by:

We can find the z score then for 20880 and 20936 and we got:


Then we can find the probability of interest with this difference:
And using the normal standard distribution or excel we got:
So then the probability that the sample mean would differ from the true mean by less than 28 dollars from the sample of 55 is approximately 0.390
Answer:
10) C or D
11) C
12) B
Step-by-step explanation:
<h3>
Answer: $7,853.16</h3>
Work Shown:
A = P*(1+r/n)^(n*t)
A = 4750*(1+0.10/2)^(2*10)
A = 12,603.164099436
A = 12,603.16
That represents the account balance after 10 years. To find the interest only, subtract off the deposit amount.
interest = A-P = 12,603.16 - 4,750 = 7,853.16
The formula to find markup amount

A new car has a sticker price of $22,150, while the invoice price paid on it was $18,780.
Original price of new car = $18,780
Sticker price of new car = 22,150
Change in price = 22,150 - 18,780 = 3370
Markup = 
= 
= 0.179446
Markup percentage = 0.179446 * 100 = 17.94%