Answer:
a^2 +b^2=c^2
Given vertices of the triangle are A(4,4),B(3,5) and C(−1,−1)
We know that slope of line passing through the points (x 1,y 1) and (x 2,y 2
) is given by m= x 2−x 1
y
2
−y
1
,x
2
=x
1
Slope of AB i.e.m
1
=
3−4
5−4
=−1
Slope of BC i.e.m
2
=
−1−3
−1−5
=
−4
−6
=
2
3
Slope of CA i.e. m
3
=
4+1
4+1
=
5
5
=1
Clearly, m
1
m
3
=−1
⇒ line segments AB and CA are perpendicular to each other i.e; the given triangle is right angled at A(4,4).
Thus the points (4,4),(3,5) and (1,1) are the vertices of a right angled triangle.
Step-by-step explanation:
I used to look at the examples i can’t remember now what it is but look at the examples
Answer: there were 692 visitors on Saturday.
Step-by-step explanation:
Let x represent the number of visitors that were there on Friday.
Let y represent the number of visitors that were there on Saturday.
Let z represent the number of visitors that were there on Sunday.
The theme park had 1099 visitors in 3 days. It means that
x + y + z = 1099- - - - - - - - - - - - - -1
There were twice as many visitors on saturday than on Friday. This means that
y = 2x
x = y/2
There were 234 more visitors on Sunday than on Saturday. This means that
z = y + 234
Substituting x = y/2 and z = y + 234 into equation 1, it becomes
y/2 + y + y + 234 = 1099
Cross multiplying by 2, it becomes
y + 2y + 2y + 468 = 2198
5y = 2198 - 468
5y = 1730
x = 1730/5
x = 346
y = 2x = 2 × 346
y = 692
z = y + 234 = 692 + 234
z = 926
l = 2w + 4
l * w = 48
We can substitute l with its value:
2w + 4 * w = 48
2w^2 + 4w - 48 = 0
2(w^2 + 2w - 24) = 0
2(w+6)(w-4) = 0
w = {4, -6}
