Answer:
0.128
Step-by-step explanation:
We know the probability for any event X is given by,
,
where p is the probability of success and q is the probability of failure.
Here, we are given that p = 0.533.
Since, we have that q = 1 - p
i.e. q = 1 - 0.533
i.e. q = 0.467
It is required to find the probability of 4 wins in the next 5 games i.e. P(X=4) when n = 5.
Substituting the values in the above formula, we get,
![P(X=4)=\binom{5}{4}\times 0.533^{5-4}\times 0.467^{4}](https://tex.z-dn.net/?f=P%28X%3D4%29%3D%5Cbinom%7B5%7D%7B4%7D%5Ctimes%200.533%5E%7B5-4%7D%5Ctimes%200.467%5E%7B4%7D)
i.e. ![P(X=4)=5 \times 0.533 \times 0.048](https://tex.z-dn.net/?f=P%28X%3D4%29%3D5%20%5Ctimes%200.533%20%5Ctimes%200.048)
i.e. ![P(X=4)=5 \times 0.533 \times 0.048](https://tex.z-dn.net/?f=P%28X%3D4%29%3D5%20%5Ctimes%200.533%20%5Ctimes%200.048)
i.e. i.e. ![P(X=4)=0.128](https://tex.z-dn.net/?f=P%28X%3D4%29%3D0.128)
Hence, the probability of 4 wins in the next 5 games is 0.128.
To get a B, you need at least 80%.
30 x 0.8 = 24
80% of 30 is 24, so you would need to get at least 24 points <3
Answer:
f(8) = -9
Step-by-step explanation:
Substitute 8 in for x.
f(8) = -2(8) + 7
f(8) = -16 + 7
f(8) = -9
1.14 per 100 or 1.14:100 or
![\frac{1.14}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1.14%7D%7B100%7D%20)
![\frac{1.14}{100} = \frac{n}{2000}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1.14%7D%7B100%7D%20%3D%20%20%5Cfrac%7Bn%7D%7B2000%7D%20%20)
I will multiply the numerator by 20 because multiplying by 20 is how 100 became 2000
22.8 cases are rejected per hour.