Find the equation of the line connecting (0, 5) and (-2, 0).
As we go from the first point to the second, x decreases by 2 and y decreases by 5. Thus, the slope of this line is m = rise / run = -5/(-2), or 5/2.
Starting with the general equation of a line in slope-intercept form, y = mx + b, substitute the knowns as appropriate to determine the value of b:
y= mx + b => 5 = (5/2)(0) + b. Then b = 5, and the desired equation is
y = (5/2)x + 5.
Check this! If we subst. the coordinates of (-2,0) into this equation, is the equation true?
0 = (5/2)(-2) + 5
Yes. So, y = (5/2)x + 5 is the desired equation.
revenge! hope that helps! thank you for my points back!
Answer:
He worked 37.5 hours.
Step-by-step explanation:
Step 1- Divide.
750÷20= 37.5
So, he worked 37 and a half hours.
Step-by-step explanation:
so, it is a quadratic equation :
-3x² + 30x - 90 = 0
the first thing we can do is divide by 3
-x² + 10x - 30 = 0
remember, the formula to solve and find the 2 solutions is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case here
a = -1
b = 10
c = -30
x = (-10 ± sqrt(100 - 4×-1×-30))/-2 =
= (-10 ± sqrt(100 - 120))/-2 = (-10 ± sqrt(-20))/-2 =
= (-10 ± sqrt(4×5)i)/-2 = (-10 ± 2×sqrt(5)i)/-2 =
= 5 ± -sqrt(5)i
x1 = 5 - sqrt(5)i
x2 = 5 + sqrt(5)i
remember, i = sqrt(-1), a complex number.