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-BARSIC- [3]
3 years ago
6

What words that match with the expression 36 (2x3)??

Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0
72x3
..............................
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lesya [120]

the moores paid $18, hope this helps

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4 years ago
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a gift box in the shape of a rectangular prism has 20 meters long, 10 meter wide and 5 meter deep. how much water can it hold
erastovalidia [21]

Answer:

1,000

Step-by-step explanation:

20

20×10×5=1,000

6 0
3 years ago
3) Find the equation of a line perpendicular to y = -3x + 7 that goes<br> through the point (-1, 2)
Alchen [17]

Step-by-step explanation:

In order to find the new equation I used the following formula :

y - y1 = m (x -x1)

* x1 & y1 are the coordinates of the given point

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3 years ago
16/7 as a mixed number
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Answer:

2 2/7

Step-by-step explanation:

7x2 = 14 so 2 would be the whole number.

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This brings us to 2 2/7

3 0
3 years ago
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A2 = [1 2 3; 4 5 6; 7 8 9; 3 2 4; 6 5 4; 9 8 7]
34kurt

Answer:

Remember, a basis for the row space of a matrix A is the set of rows different of zero of the echelon form of A.

We need to find the echelon form of the matrix augmented matrix of the system A2x=b2

B=\left[\begin{array}{cccc}1&2&3&1\\4&5&6&1\\7&8&9&1\\3&2&4&1\\6&5&4&1\\9&8&7&1\end{array}\right]

We apply row operations:

1.

  • To row 2 we subtract row 1, 4 times.
  • To row 3 we subtract row 1, 7 times.
  • To row 4 we subtract row 1, 3 times.
  • To row 5 we subtract row 1, 6 times.
  • To row 6 we subtract row 1, 9 times.

We obtain the matrix

\left[\begin{array}{cccc}1&2&3&1\\0&-3&-6&-3\\0&-6&-12&-6\\0&-4&-5&-2\\0&-7&-14&-5\\0&-10&-20&-8\end{array}\right]

2.

  • We subtract row two twice to row three of the previous matrix.
  • we subtract 4/3 from row two to row 4.
  • we subtract 7/3 from row two to row 5.
  • we subtract 10/3 from row two to row 6.

We obtain the matrix

\left[\begin{array}{cccc}1&2&3&1\\0&-3&-6&-3\\0&0&0&0\\0&0&3&2\\0&0&0&2\\0&0&0&2\end{array}\right]

3.

we exchange rows three and four of the previous matrix and obtain the echelon form of the augmented matrix.

\left[\begin{array}{cccc}1&2&3&1\\0&-3&-6&-3\\0&0&3&2\\0&0&0&0\\0&0&0&2\\0&0&0&2\end{array}\right]

Since the only nonzero rows of the augmented matrix of the coefficient matrix are the first three, then the set

\{\left[\begin{array}{c}1\\2\\3\end{array}\right],\left[\begin{array}{c}0\\-3\\-6\end{array}\right],\left[\begin{array}{c}0\\0\\3\end{array}\right] \}

is a basis for Row (A2)

Now, observe that the last two rows of the echelon form of the augmented matrix have the last coordinate different of zero. Then, the system is inconsistent. This means that the system has no solutions.

4 0
3 years ago
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