If the width of the garden is w, then the maximum area available is a square, giving you w² as the dimensions. So:
w²=-w²+28w
2w²=28w
w=14
The perimeter is 14 x 4, or 56 feet
How many seed packets??? No idea
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7 0

3 years ago

Consider the following cumulative probability distribution.

Marat540 [252]

The solution $P(x \leq 4),p{x= 3), p(2 \leq * \leq 4)$ is mathematically given as

$P(2 \leq X \leq 4)=0.84$
P(X=3)= 0.17

$P(2 < =X\leq 4)=0.53$

<h3>What is the solution $P(x \leq 4),p{x= 3), p(2 \leq * \leq 4)$ ?</h3>

Generally, the equation for the Probability of P(X=3) is mathematically given as

$P(X=3) = P(X \leq 3)-P(X\leq 2)$

Therefore

$P(X=3)= 0.65-0.48$

P(X=3)= 0.17

$P(2\leq X\leq 4) = P(X\leq 4)-P(X\leq 1)\\\\\\P(2\leq X\leq 4) = 0.84-0.31'$

$P(2 < =X\leq 4)=0.53$

$P(2\leq X\leq 4)=0.84$

Read more about cumulative probability distribution.

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7 0

2 years ago

Simplify the following 3√28-5√63+4√112

alexandr402 [8]

7√7

using the ' rule of radicals '

• √a × √b ⇔ √ab

simplifying the radicals

√28 = √(4 × 7 ) = √4 × √7 = 2√7

√63 = √(9 × 7) =√9 × √7 = 3√7

√112 = √(16 × 7 ) = √16 × √7 = 4√7

substituting into the expression

3(2√7) - 5(3√7) + 4(4√7) = 6√7 - 15√7 + 16√7 = 7√7

7 0

3 years ago

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