Which expression is equivalent to ? Assume

PLEASE HELP‼️‼️Drag the expression that is the most reasonable measurement for each object.

Afina-wow [57]

Answer:

A. Length of a Tour Bus ↔ #2. 1.1 × 10¹ meters

B. Width of an apple ↔ #3. 4 × 10⁰ centimeters

C. Distance from Earth to a Satellite ↔ #6. 8 × 10² kilometers

D. Thickness of a human hair ↔ #5. 9 × 10¹ micrometers

Explanation:

A. Length of a tour bus.

The length of a tour bus should be measured in meters. It sure is way less than 1 kilometer and way more than a few centimeters. It could be about some meters, more than 5 meters, may be between 10 meters and 15 meters.

The measurement in the box # 2. is 1.1 × 10¹ meters, which is equivalent to 1.1 × 10meters = 11 meters. Thus, this is a reasonable length.

B. Width of an apple.

The most appropiate unit to measure the width of an apple should be centimer. It certanly is shorter than 1 meter and bigger than 1 mm.

The width of an apple could be, more or less, around 8 centimeters. The only measurement in the boxes that is in that order is that in the box #3., 4 × 10⁰ centimeters, because 10⁰ = 1, so 4 × 10⁰ = 4 × 1 = 4centimeters.

C. Distance from Earth to a Satellite

The distance from Earth to a satellite should be measured in kilometers.

You can find in the internet that the distances of the satellites are between 700 kilometers and 36,000 kilometers.

The number in the box #1 is too big, in the order of ten trillions of kilometers, because one trillion is 10¹²; thus that is notreasonalbe (too big).

The number in the box #6 is 8 × 10² kilometers, which is equal to 8 × 100 = 800 kilometers.

Thus, 8 × 10² kilometers (box #6) is the most reasonable measurement for the distance from Earth to a Satellite

D. Thickness of a human hair

Of course, kilometers, meters, centimeters and even milimeters are units too big to measure the thickness of a human hair.

One micrometer is 10⁻⁶ meters or 10⁻³ milimeters.

In the internet you can find that diameter of the humar hairis in the range from 17 micrometers to 181 micrometers.

The measurement in the box #5. is 9 × 10¹ micrometers, which is equivalent to 9 × 10 = 90 micrometers.

Thus, 9 × 10¹ micrometers is the most reasonable measurement fot the thickness of a human hair.

7 0

3 years ago

Ayana has 220 coins in her piggy bank Of those 40percent are pennies. Out of the coins that are not pennies 25 percent are partn

Rzqust [24]

To find a percent of a number, multiply the percent by the number.

First we find the number of pennies.

40% of 220 =

= 40% * 220

= 0.4 * 220

= 88

88 coins are pennies.

220 - 88 = 132

132 coins are not pennies.

Now we find 25% of 132.

25% of 132 =

= 25% * 132

= 0.25 * 132

= 33

33 coins are partners.

(Did you mean quarters instead of partners?)

3 0

3 years ago

Using the bijection rule to count binary strings with even parity.

AleksandrR [38]

Answer:

Lets denote c the concatenation of strings. For a binary string a in B9, we define the element f(a) in E10 this way:

f(a) = a c {1} if a has an odd number of 1's
f(a) = a c {0} if a has an even number of 1's

Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:

If x has an even number of 1's, then the last digit of y has to be 0, and f(x) = x c {0} = y
If x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = y

This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

3 0

3 years ago

Help please!!!.......

Nitella [24]

It is isi s is is is a

4 0

3 years ago

Show that 6x^2+17x-39=0

8_murik_8 [283]

I hope this helps you

4 0

3 years ago