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poizon [28]
3 years ago
13

On a scale if 2.5 cm represents 620 miles what does 1 cm represent in the actual distance?​

Mathematics
1 answer:
Anni [7]3 years ago
7 0

Answer:

2.5 cm = 620miles

1cm = ??

1cm = (620÷2.5) miles

1cm = 248miles.

BY GERALD GREAT

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......i need help please..........​
makkiz [27]

Answer:

Step-by-step explanation:

So, TML = 104, right?

Now, we know that TMV + LMV is 104.

We also know that TMV is 60.

Sooooo

LMV is simply 104 - 60 = 54

LMV = 54 :)

5 0
3 years ago
Read 2 more answers
PLEASE HELP ME
Vlada [557]

Answer:

  • x = 0
  • x = 1

Step-by-step explanation:

Find two rows in the table that have the same values in the f(x) and g(x) columns.

6 0
3 years ago
a rally car course covers 51 5.97 miles .the winning car completed the course in 6.5 hours. what was the average speed of the wi
Artyom0805 [142]
Assuming the speed is in miles per hour, simply divide the total distance by time.
515.97/6.5
The answer is 79.38 miles per hour
5 0
4 years ago
How do I find the area of each shape
Ad libitum [116K]

Answer: the formula is (A=bh1/2)


Step-by-step explanation: #4 (The triangle)

First let’s find the base length of the triangle.

28 - 16 = 12

Ok now let’s do the real math now

Area  = bh1/2

Area = (12)(16)(1/2)

Area = 96

Don’t worry about the slant height it’s just there to trick you  




8 0
3 years ago
HELP!
Alexxx [7]

Answer:

LIMIT

The policy will pay for up to

$100,000 of damage to

another person's property.

The policy will pay only

$100 per incident for a

tow truck

DEDUCTIBLE

The policyholder must pay

the first $1,000 of repair

expenses before insurance

will pay for anything,

PREMIUM

The policy offers coverage

for a cost of $178 per month

The policyholder must

pay $500 semiannually

to the insurance provider

Step-by-step explanation:

LIMIT is the maximum amount an insurer will pay toward a covered claim

DEDUCTIBLE is the amount paid out of pocket toward a covered claim

PREMIUM is the amount paid regularly to keep the policy in force.

6 0
3 years ago
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