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solniwko [45]
2 years ago
12

Can someone help me with this? please​

Mathematics
1 answer:
elixir [45]2 years ago
8 0

Answer:

14.4 feet

Step-by-step explanation:

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PLEASE HELP I HAVE 5 MINUTES LEFT AND IM HALFWAY DONE PLEASE HELP ASDHA;EFhTHS
galben [10]

Answer:

12 is 52 i think. i am not sure about 11.

Step-by-step explanation:

im so sorry i know 11:(

I hope this helps on 12 tho

7 0
3 years ago
The width of a rectangle is six meters less than three times its length. If the area of the rectangle is 105 square meters. what
Kipish [7]

Answer:

length = 7 meters

Step-by-step explanation:

l = length

w = width

w = 3×l - 6

l×w = 105 m²

l×(3×l - 6) = 105

3×l² - 6×l = 105

l² - 2×l = 35

l² - 2×l - 35 = 0

solution of a squared equation is

(-b ± sqrt(b² - 4ac))/(2a)

a = 1

b = -2

c = -35

(2 ± sqrt(4 - 4×-35))/2 = (2 ± sqrt(4+140))/2 =

(2 ± sqrt(144))/2 = (2 ± 12)/2 = 1 ± 6

l1 = 1+6 = 7 meters

l2 = 1-6 = -5 meters, which did not make any sense for an actual object.

so, l = 7 meters remains.

7 0
3 years ago
Uranus moves in an elliptical orbit with the sun at one of the foci. The length of the half of the major axis is 2,876,769,540 k
Alina [70]

Answer:

The minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.

Step-by-step explanation:

Consider the provided information.

The length of the half of the major axis is 2,876,769,540 kilometers, and the eccentricity is 0.0444.

The eccentricity (e) of an ellipse is the ratio of the distance from the center to the foci (c) and the distance from the center to the vertices (a).

e=\frac{c}{a}

Substitute a = 2,876,769,540 and e = 0.0444 in above formula and solve for c.

0.0444=\frac{c}{2,876,769,540 }

c=127728567.576

Minimum distance of Uranus from the sun is:

a-c=2,876,769,540-127728567.576\\a-c=2749040972.424\approx2749040972

Hence, the minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.

6 0
3 years ago
What is the surface area of the triangular prism?
miv72 [106K]

Answer:

168ft

Step-by-step explanation:

1/2(6)(4)=12

1/2(6)(4)=12

(9)(5)=45

(9)(5)=45

(9)(6)=54

12+12+45+45+54=168

6 0
3 years ago
Clint wants to keep a young tree from blowing over during a high wind.he decides that he should tie a rope around the tree at a
liraira [26]
The rope tied to the tree will make a triangle.

The height of the triangle = 180cm
The base of the triangle = 200cm

to find how much rope you need, work out the hypotenuse using Pythagoras:

180^2 + 200^2 = 72400
√72400 = 269.0724809

This is the length of rope he needs, however you need to +30 as this is what he will need when he ties the rope:

269.0724809 + 30 = 299.0724809

299.0724809 is less than the 270cm of rope he has, so he would need more.

8 0
3 years ago
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