PLEASE HELP ASAP Due in 1 day!!!
1 answer:
Step-by-step explanation:
Q1 . (f+g)(x) = f(x) + g(x)
=4x-4 +2x^2 -3x
= 2x^2 + x -4
Q2. (f-g)(x) = f(x) - g(x)
= 2x^2−2 - (4x+1)
= 2x^2 -2 -4x -1
= 2x^2 - 4x -3
Q3. h(x)=3x−3 and g(x)=x^2+3
(h.g)(x) = h(x) × g(x)
= (3x-3) × (x^2 + 3)
=3x^3 -3x^2 + 9x -9
Q4.f(x)=x+4 and g(x)=x+6
(f/g)(x) = f(x) ÷ g(x)
= x+4 / x+6
the domain restriction is x>-6
x<-6
x doesn't equal (-6)
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Answer:
Step-by-step explanation:
The maths teacher because it was the first day back but he was giving a ‘miD YeAr tEsT’
the bells will ring at 3:00pm
Use quadratic formula
for ax^2+bx+c=0
x=
given
2x^2+23x-19=0
a=2
b=23
c=-19
x=
x=
x=
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or
9 x 8 = 72
9 + 9 +9 + 9 + 9 +9 + 9 + 9 = 72
Answer:
0.72
Step-by-step explanation:
7.25+2.35=9.6
9.6÷100=0.096
0.096×7.5=0.72 the tax
