Answer:
With few exceptions, all cells in a person’s body have the same DNA and genes. As cells divide and grow different genes are expressed, resulting in different cell types. As cells divide and grow different genes are expressed, resulting in different cell types.
Explanation:
Competitive inhibition vs allosteric inhibition
In competitive the substrate and inhibitor bind at the same active site - pretty straightforward. In allosteric regulation (speaking specifically about inhibition here), the inhibitor is binding at a site other than the active site, and changing the enzyme in some way to make it inactive.
Answer:
See the answer below
Explanation:
<em>Recall that the law of dilution states that the number of moles before dilution must be equal to the number of moles after dilution.</em>
Mathematically,
molarity x number of moles before dilution = molarity x number of moles after dilution.
For solution A: final molarity = 3 mM, final volume = 2mL, initial molarity of KMnO4 = 10 mM
Applying the equation:
10 x initial volume = 3 x 2
initial volume = 6/10 = 0.6
<u>Hence, Tube A should be made with 0.6 mL of 10 mM KMnO4 stock and 1.4 mL of distilled water to give a solution of 2 mL 3 mM KMnO4.</u>
For solution B:final molarity = 8 mM, final volume = 2 mL, initial molarity = 10 mM
10 x initial volume = 8 x 2
initial volume = 16/10 = 1.6
<u>Hence, Tube B should be made with 1.6 mL of 10 mM KMnO4 stock and 0.4 mL of distilled water to give a solution of 2 mL 8mM KMnO4. </u>
Answer:
In acid-fast staining, carbon fuchsin is used as a primary stain which dissolves the mycolic acid present in the cell wall of <em>Mycobacterium smegmatis </em>and penetrates through it which results in staining <em>Mycobacterium</em> red.
Staphylococcus aureus cell wall does not contain mycolic acid so carbon fuchsin does not penetrate its cell wall, therefore, it becomes colorless after destaining with acid alcohol.
After destaining step methylene blue is added to stain non-acid-fast bacteria blue. So if I mistakenly forgot to use methylene blue during the procedure <em>Mycobacterium smegmatis</em> will appear red due to carbon fuchsin present in their cell wall and S<em>taphylococcus aureus</em> will appear colorless because it is destained.
Liters/cl/ml/dl for liquids and cubic meters/cm/mm/km for solids
