The possible permutations are 6P3 which is 120. Out of those there are 7 ways to get 6 with three dice. So P(6)=7/120
Step-by-step explanation:
Tn = a + (n - 1) d
Where
Tn is the nth term of the sequence
a is the first term of the sequence
n is the number/term of the sequence to be solved
d is the common difference
Answer:
second option
Step-by-step explanation:
Given
+ 6x² + 5 = 0
let u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Change u back into terms of x, that is
x² = - 1 ( take the square root of both sides )
x = ± = ± i ( noting that = i ), and
x² = - 5 ( take the square root of both sides )
x = ± = ± = ± × = ± i
Solutions are x = ± i and x = ± i
Step-by-step explanation:
2x+98=180° (angles in straight line )
2x=180-98
x=2/2
x=1