Corey measure a crayon box writhing his paper clip ruler. about how long is the box

This is Daniela’s work to solve the equation 13 x + 42 = 276.

Yuliya22 [10]

Answer:
Subtraction property of equality.

4 0

3 years ago

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Consider trapezoid LMNO.

jenyasd209 [6]

The side LO is congruent to the side MN, the diagonal LN is congruent to the diagonal MO, and the angle L is congruent to the angle M in an isosceles trapezoid, denoted by the symbols LMNO.

What are the conditions for an Isosceles Trapezoid?

The conditions listed below demonstrate that any trapezoid is an isosceles trapezoid:

The length of both legs is the same.
2nd condition: The base angles are of equal proportion.
The length of the diagonals is the same.

When these conditions are met by the given trapezoid LMNO, it will be referred to as an isosceles trapezoid. Hence, the following conditions of trapezoid LMNO need to be fulfilled,

LN ≅ MO

LO ≅ MN

∠L ≅ ∠M

Learn more about a trapezoid here:

brainly.com/question/26335898

#SPJ1

3 0

2 years ago

Suppose an amount increases by 100% percent, then decreases by 100% percent. Find the final amount. Would the situation change i

Oksi-84 [34.3K]

No it will not change it will be 250% then it will decrease 100% down again back to 150%

6 0

3 years ago

karita has $138.72 in her checking account she wrote checks for $45.23 and $18 then she made a deposit of $75.85 into her accoun

il63 [147K]

Answer:

She should have about $150

Step-by-step explanation:

If you round all the numbers you get..

140-50-20+80

140-50-20=70

70+80=150

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3 years ago

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Kristen invests $ 5745 in a bank. The bank 6.5% interest compounded monthly. How long must she leave the money in the bank for i

podryga [215]

Answer:

1. 10.7 years

2. 17.0 years

3. 2nd option

Step-by-step explanation:

Use formula for compounded interest

$A=P\cdot \left(1+\dfrac{r}{n}\right)^{nt},$

where

A is final value, P is initial value, r is interest rate (as decimal), n is number of periods and t is number of years.

In your case,

1. P=$5745, A=2P=$11490, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$11490=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},\\ \\2=(1.0054)^{12t},\\ \\12t=\log_{1.0054}2,\\ \\t=\dfrac{1}{12}\log_ {1.0054}2\approx 10.7\ years.$

2. P=$5745, A=3P=$17235, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$17235=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},$

$3=(1.0054)^{12t},$

$12t=\log_{1.0054}3,$

$t=\dfrac{1}{12}\log_{1.0054}3\approx 17.0\ years.$

3. <u>1 choice:</u> P=$5745, n=12 (compounded monthly), r=0.065 (6.5%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12\cdot 5},\\ \\A=5745\cdot (1.0054)^{60}\approx \$7936.39.$

<u>2 choice:</u> P=$5745, n=4 (compounded monthly), r=0.0675 (6.75%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.0675}{4}\right)^{4\cdot 5},\\ \\A=5745\cdot (1.0169)^{20}\approx \$8032.58.$

The best will be 2nd option, because $8032.58>$7936.39

5 0

3 years ago

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