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3 years ago

6

Find the distance between (43,-15) & (29,-3)

2 answers:

aleksley [76]3 years ago

8 0

D^2 = (x2 - x1)^2 + (y2 - y1)^2

(x,y)
(43,-15) & (29,-3)

x1 = 43 , y1 = -15
x2 = 29 , y2 = -3

d^2 = (29-43)^2 + (-3--15)^2
d^2 = (-14)^2 + (12)^2
d^2 = 196 + 144
d^2 = 340
d = sqrt(340)
d = 2*sqrt(85)
d = 18.44

Sergio [31]3 years ago

3 0

Distance = Square Root ( (X difference)^2<span> + (Y difference)^</span>2<span> )
</span>Distance = Square Root [( 43 -29)^2 + (-15 --3)^2]
Distance = Square Root (14^2 + -12^2)
Distance = Square Root (340)
Distance = <span> <span> <span> 18.4390889146 </span> </span> </span>

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4 years ago

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Read 2 more answers

12. (24.4D) For what value of c will the graphs of

weqwewe [10]

Answer:

$c=144$

Step-by-step explanation:

we have

$y=2x^2-36x+c$ ---> equation A

$y=2(x-9)^2-18$ ---> equation B

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