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natali 33 [55]
3 years ago
6

Find the distance between (43,-15) & (29,-3)

Mathematics
2 answers:
aleksley [76]3 years ago
8 0
D^2 = (x2 - x1)^2 + (y2 - y1)^2


(x,y)
(43,-15) & (29,-3)

x1 = 43 , y1 = -15
x2 = 29 , y2 = -3


d^2 = (29-43)^2 + (-3--15)^2
d^2 = (-14)^2 + (12)^2
d^2 = 196 + 144
d^2 = 340
d = sqrt(340)
d = 2*sqrt(85)
d = 18.44
Sergio [31]3 years ago
3 0
Distance = Square Root ( (X difference)^2<span> + (Y difference)^</span>2<span> )
</span>Distance = Square Root [( 43 -29)^2 + (-15 --3)^2]
Distance = Square Root (14^2 + -12^2)
Distance = Square Root (340)
Distance = <span> <span> <span> 18.4390889146 </span> </span> </span>


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Answer:

m∠1 = 63°

m∠2 = 49°

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Step-by-step explanation:

From the given figure

∵ ∠2 and 49° are vertically opposite angles

∵ The vertical opposite angles are equal in measures

∴ m∠2 = 49°

∵ The sum of the interior angles of a Δ is 180°

∵ m∠1, m∠2, and 68° are interior angles of a Δ

∴ m∠1 + m∠2 + 68° = 180°

∵ m∠2 = 49°

∴ m∠1 + 49° + 68° = 180°

→ Add the like terms in the left side

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→ Subtract 180 from both sides

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∵ ∠3 and 93° formed a pair of linear angles

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→ Subtract 93 from both sides

∴ m∠3 = 87°

∵ 93° is an exterior angle of the triangle

∵ The measure of the exterior angle of a Δ at one vertex equals the sum

   of the measures of the opposite interior angles to this vertex

∵ ∠4 and 49° are the opposite interior angles to 93°

∴ 49° + m∠4 = 93°

→ Subtract 49 from both sides

∴ m∠4 = 44°

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