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grandymaker [24]
2 years ago
10

What is the sum of the series 1 + ln3 + (ln3)^2/2!?

Mathematics
1 answer:
tresset_1 [31]2 years ago
5 0
\displaystyle\sum_{n\ge0}\frac{(\ln3)^n}{n!}=e^{\ln3}=3

which follows from the power series representation for e^x,

e^x=\displaystyle\sum_{n\ge0}\frac{x^n}{n!}

and taking x=\ln3.
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If 18 is added to a certain number and the sum is divided by 6, the result is 1 more than 14 of the original number. Find the or
Katyanochek1 [597]
The original number is 72 


(18+x)/6 = 1+14 
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Answer:

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Step-by-step explanation:

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