<span>1.Describe how the graph of y = x2 can be transformed to the graph of the given equation.
y = (x+17)2
Shift the graph of y = x2 left 17 units.
2.Describe how the graph of y= x2 can be transformed to the graph of the given equation.
y = (x-4)2-8
Shift the graph of y = x2 right 4 units and then down 8 units.
.Describe how to transform the graph of f into the graph of g.
f(x) = x2 and g(x) = -(-x)2
Reflect the graph of f across the y-axis and then reflect across the x-axis.
Question 4 (Multiple Choice Worth 2 points)
Describe how the graph of y= x2 can be transformed to the graph of the given equation.
y = x2 + 8
Shift the graph of y = x2 up 8 units.
Question 5 (Essay Worth 2 points)
Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch.
f as a function of x is equal to the square root of x and g as a function of x is equal to 8 times the square root of x
f(x) = √x, g(x) = 8√x
vertical stretch factor 8
Plz mark as brainlest</span>
Answer:
................Uhm not a question.....................................................o/o
Answer:
I assume AC = 49.89 since the number is cut off
Step-by-step explanation:
tangent(degree) = opposite / adjacent
To find AC, you can set up tan(29) = AC / CB
tan(29) = AC / 90 (the picture is cutted off, so I assume....)
= AC
Answer:
3√2 or 4.24
Step-by-step explanation:
d(w,x) = √(5-2)² + (-4-(-7))² = √18 = 3√2 (4.24)
For this case we have the following function:
![f (x) = 2x ^ 2 + \frac {5} {x-2}](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%202x%20%5E%202%20%2B%20%5Cfrac%20%7B5%7D%20%7Bx-2%7D)
By definition, we have that the domain of a function is given by all the values for which the function is defined. The given function is not defined when the denominator is zero.
So:
![x-2 = 0\\x = 2](https://tex.z-dn.net/?f=x-2%20%3D%200%5C%5Cx%20%3D%202)
Thus, the function is not defined at ![x = 2.](https://tex.z-dn.net/?f=x%20%3D%202.)
The domain is given by all real numbers except 2.
Answer:
The domain is given by all real numbers except 2.