Answer:
4334.4 J
Explanation:
Work done equals to kinetic energy change
KE=½mv²
Change in KE is given by
∆KE=½m(v²-u²)
Where m is mass of water-skier, KE is kinetic energy, ∆KE is the change in kinetic energy, v is final velocity and u is initial velocity.
Substituting 72 kg for m, 12.1 m/s for v and 5.10 m/s for u then
∆KE=½*72(12.1²-5.10²)=4334.4J
Therefore, the work done by the net external force acting on the skier is equal to 4334.4 J
Answer:
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Explanation:
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Answer:

Explanation:
The correct formula for the potential energy between two atoms in a particular molecule is:

Where
is the distance.
According to the definitions of potential energy and work, as well as the Work-Energy Theorem and the Principle of Energy Conservation. The relation between that and related force is:

The function is derived in terms of distance:

Then, it is needed to find at least of x so that F(x) equals to 0.



![x=\sqrt[4]{\frac{84}{104} }](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B84%7D%7B104%7D%20%7D)

Answer:
a. 475.14 Hz
b. 1959 Hz
c. 2341.53 Hz , 3053.34 Hz
Explanation:

a. smallest use the capacitive 4.2 uF + 6.0 uF = 10.2uF replacing:


b. second smallest use the capacitive 6 uF so:


c. second largest and largest oscillation first combination so:
Use 4.2 uF


And finally largest oscillation cap in serie so:




Answer:
(a) Magnitude: 14.4 N
(b) Away from the +6 µC charge
Explanation:
As the test charge has the same sign, the force that the other charges exert on it will be a repulsive force. The magnitude of each of the forces will be:

K is the Coulomb constant equal to 9*10^9 N*m^2/C^2, q and qtest is the charge of the particles, and r is the distance between the particles.
Let's say that a force that goes toward the +6 µC charge is positive, then:


The magnitude will be:
, away from the +6 µC charge