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vivado [14]
2 years ago
13

Development of the Grand Canyon through the uplift of the plateau and erosion by the Colorado River illustrates that:

Physics
2 answers:
MAXImum [283]2 years ago
7 0
Landforms result from a combination constructive and destructive forces.
Hope this helps
Fittoniya [83]2 years ago
4 0

Answer:

<em><u>The answer is</u></em>: <u>The Grand Canyon is a testament to the erosive power of water. This modified model seems to be the predominant theory among today's evolutionary geologists.</u>

<u />

Explanation:

<u>The Grand Canyon is one of the most impressive erosive features in the world</u>.

Carved through sedimentary layers of sandstone, limestone and shale and in the basement formations of mostly metamorphic shales and igneous granites, the Grand Canyon is a testament to the erosive power of water.

<u>The now widely accepted theory</u> has the capture of the current that takes place in one of the northwest drains that is believed to have existed before the elevation of the plateau.

<u>It was believed that the ancestral Colorado River had turned north,</u> draining into the Great Salt Lake region.

<u>Once again</u>, once the capture was carried out, the plateau rose, which caused the drains that tend to the northwest to flow into the Colorado River.

This modified model seems to be the predominant theory among today's evolutionary geologists.

<em><u>The answer is</u></em>: <u>The Grand Canyon is a testament to the erosive power of water. This modified model seems to be the predominant theory among today's evolutionary geologists.</u>

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An electromagnetic flowmeter is useful when it is desirable not to interrupt the system in which the fluid is flowing (e.g. for
AURORKA [14]

Answer:

<em>2 m/s</em>

<em></em>

Explanation:

The electromagnetic flow-metre work on the principle of electromagnetic induction. The induced voltage is given as

E = Blv

where E is the induced voltage = 2.88 mV = 2.88 x 10^-3 V

l is the distance between the electrodes in this field which is equivalent to the diameter of the tube = 1.2 cm = 1.2 x 10^-2 m

v is the velocity of the fluid through the field = ?

B is the magnetic field = 0.120 T

substituting, we have

2.88 x 10^-3 = 0.120 x 1.2 x 10^-2 x v

2.88 x 10^-3 = 1.44 x 10^-3 x v

v = 2.88/1.44 = <em>2 m/s</em>

8 0
3 years ago
A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio
Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

5 0
3 years ago
According to Coulomb's law, if the separation between two particles of the same charge increases four times, the potential energ
Lera25 [3.4K]

Answer:

c.   V = k Q1 * Q2 / R1      potential energy of Q1 and Q2 separated by R

V2 / V1 = (R1 / R2) = 1/4

V2 = V1 / 4

8 0
2 years ago
A 36.3 kg cart has a velocity of 3 m/s. How much kinetic energy does the object have?
uysha [10]

Answer:

163.35

__________________________________________________________

<u>We are given:</u>

Mass of the object (m) = 36.3 kg

Velocity of the object (v) = 3 m/s

<u>Kinetic Energy of the object:</u>

We know that:

Kinetic Energy = 1/2(mv²)

KE = 1/2(36.3)(3)²            [replacing the variables with the given values]

KE = 18.15 * 9

KE = 163.35 Joules

Hence, the cart has a Kinetic Energy of 163.35 Joules

7 0
2 years ago
A 90 kg body is taken to a planet where the acceleration due to
Serggg [28]

Answer:

2250N

Explanation:

W= mg,

where W= weight

m= mass

g= acceleration due to gravity

Given that the body is 90kg, m= 90kg.

Acceleration due to gravity of planet

= 2.5(10)

= 25 m/s²

Weight of body on planet

= 90(25)

= 2250N

*Mass is the amount of matter an object has and is constant (same on earth and the planet).

6 0
3 years ago
Read 2 more answers
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