To get your answer, you will need to find the perpendicular slope for -1/3x which is just the opposite therefore it will be 3x. Your slope is 3x as perpendicular so use this slope to do point slope. Y-1=3(x-2). Distribute y-1=3x-6. Add 1 to both sides. (-1+1) (-6+1)=-5. So your equation in slope intercept form is y=3x-5. Going through the two points.
Hope this helps!
The equation that offers the best approximation to this result is:
. (Choice D)
<h3>How to find the free fall formula for a given scenario</h3>
An object experiments a free fall when it is solely accelerated by gravity on the assumption of an <em>uniform</em> acceleration. The formula is described below:
(1)
Where:
- Initial height, in feet.
- Initial speed, in feet per second.
- Time, in seconds.
- Gravitational acceleration, in feet per square second.
If we know that
,
,
,
, then the height formula is:



The equation that offers the best approximation to this result is:
. (Choice D)
To learn more on free fall, we kindly invite to check this verified question: brainly.com/question/13796105
Answer:
x = 20
Step-by-step explanation:
These angles are consecutive interior angles, so when added they will equal 180 degrees (according to the consecutive interior angles theorem).
3x - 10 + 5x + 30 = 180 add/subtract all like terms
8x + 20 = 180
8x = 160
x = 20 <--- This will be your answer
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Answer:
Yes, distance is never negative.
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 25235
For the alternative hypothesis,
µ > 25235
This is a right tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 100,
Degrees of freedom, df = n - 1 = 100 - 1 = 99
t = (x - µ)/(s/√n)
Where
x = sample mean = 27524
µ = population mean = 25235
s = samples standard deviation = 6000
t = (27524 - 25235)/(6000/√100) = 3.815
We would determine the p value using the t test calculator. It becomes
p = 0.000119
Since alpha, 0.05 > than the p value, 0.000119, then we would reject the null hypothesis. There is sufficient evidence to support the claim that student-loan debt is higher than $25,235 in her area.