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vampirchik [111]
3 years ago
9

In a race, the-second place finisher crossed the finish line 1 1/3 minutes after the winner. The third-place finisher was 1 3/4

minutes behind the second-place finisher. The third-place finisher took 34 2/3 minutes. How long did the winner take?
PS: Solve the problem using the RDW strategy. Show all of your work.
Mathematics
2 answers:
KiRa [710]3 years ago
8 0

Answer:

First Winner take 31.95 minute time to complete race.

Step-by-step explanation:

Since the third winner take 34\frac{2}{3} minutes to complete the race.

Second winner take 1\frac{3}{4} minutes less than Third Winner.

Thus Second winner take 34\frac{2}{3}-1\frac{3}{4}\\  \frac{104}{3}-\frac{7}{4}\\ \frac{395}{12} =32.92 \ minutes

Also, First winner take 1\frac{1}{3} minutes less time.

Thus first winner take time = \frac{395}{12}-1\frac{1}{13}\\ \frac{395}{12}-\frac{14}{13}=31.95 minutes

Soloha48 [4]3 years ago
4 0

Answer:31 7/12

Answer:31 7/12

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Rudiy27

Hello there!


5d = 17.1

The equation is asking you to find the value for "d". How to do that? Well, all you have to do is divide both side by 5.

5d/5 = 17.1

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That's your answer!


You can even double check your work, if you want to. How? Well, you just need to replace 3.42 where it belongs.

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True!


Let me know if you have additional questions. As always, it is my pleasure to help students like you!

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