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3 years ago

Find the distance between (-18, 9) and (22,0).

Mathematics

2 answers:

Bumek [7]3 years ago

3 0

Answer:

Step-by-step explanation:

svp [43]3 years ago

3 0

For answer refer to the attachment

If it helps you plzz brainliest me..

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melomori [17]

You multiply straight across, and one number is a fraction and the other is not.

3 0

3 years ago

Add. –32.7+(–0.2)<br> a. –32.9<br> b. –32.5<br> c. 32.5<br> d. 32.9

yKpoI14uk [10]

The answer to your question is -32.9

5 0

3 years ago

Find the circumference of a circle with an area of 676pi

saveliy_v [14]

Answer:

The circumference of the circle is 52π

Step-by-step explanation:

To solve this exercise we first have to calculate the radius of the circle, for this we will use the formula of area of a circle and we will clear the radius

a = area = 676π

r = radius

a = π * r²

we clear r

r = √(a/π)

now we replace the known values

r = √(676π/π)

r = √(676)

r = 26

now we use the formula to calculate the circumference of a circle

c = π * 2r

c = π * 2 * 26

c = 52π

The circumference of the circle is 52π

6 0

2 years ago

Read 2 more answers

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

2 years ago

if angle RZT=110, angle RZS=3s, and angle TZS=8s, what are angle RZS and angle TZS?

skelet666 [1.2K]

8s-3s=5s
5s=110
Divide both sides by 5 => s=22
RZS = 3s = 3(22) = 66
TZS= 8s = 8(22) = 176

7 0

2 years ago