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tamaranim1 [39]
3 years ago
6

A landscaper buried a water line around a rectangular lawn to serve as a supply line for a sprinkler system. The length of the l

awn is 6 times its width. If 630 feet of pipe was used to do the job, what is the length and the width of the lawn
Mathematics
1 answer:
Orlov [11]3 years ago
7 0

Answers:

Length = 270 feet

Width = 45 feet

========================================================

Work Shown:

x = width

6x = length, since it is 6 times the width

P = perimeter of rectangle

P = 2*(Length + Width)

P = 2*(6x + x)

P = 2*(7x)

P = 14x

Plug in the given perimeter P = 630 and solve for x.

P = 14x

14x = P

14x = 630

x = 630/14

x = 45

The width is 45 feet.

The length must be 6x = 6*45 = 270 feet.

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2 years ago
A department store has a discount on shoes based on percentage of the price. Suppose one pair of shoes is marked down 70$ to 49$
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=> one pair of shoes marked down from 70 dollars to 49  dollars
=> let’s solve for the percentage rate.
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8 0
4 years ago
The volume V of a right‑circular cylinder is computed using the values d = 3.1 m for the diameter and h = 6.6 m for the height.
pantera1 [17]

Answer:

6%

Step-by-step explanation:

A function f(x) can by approximated at and around a point, say x = a by,

f(x) = f(a) + f'(a)(x-a)

where,  f'(x)=\frac{df}{dx}

Here, volume V is a function of radius r and height h. In the 2 dimensional case, we have to take the partial derivatives.

Given,

V=\pi r^2h

or, dV=\frac{\partial V }{\partial r}dr+ \frac{\partial V }{\partial h}dh

at r = 1.55 m and h = 6.6 m

dr=0.02\times1.55m=0.031m

dh=0.02\times6.6m=0.132m

\frac{\partial V }{\partial r}=2\pi r h=2\pi \times 1.55\times 6.6=64.277

\frac{\partial V }{\partial h}=\pi r^2=7.5477

Therefore, dV=(64.277\times.031)+(7.5477\times0.132)=2.9889m

Also, V=\pi r^2h=49.8147m

Hence, maximum error is given by,

R=\frac{2.9889}{49.8147} \times 100

= 6%

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4 years ago
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