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Kisachek [45]
3 years ago
12

Please help thanks gryrrjfjti

Mathematics
1 answer:
lara [203]3 years ago
5 0

9514 1404 393

Answer:

     207.24 in²

Step-by-step explanation:

The "r" in the formula stands for the radius of the cylinder. That is half the diameter, so is 3 in. The "h" in the formula stands for the cylinder height, shown as 8 in. Put these values in the formula and do the arithmetic.

  SA = 2πr(r +h) = 2(3.14)(3 in)(3 in + 8 in) = 6.28(33 in²)

  SA = 207.24 in²

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Hmmmm let's see hmmm let's try with any number.. say  25

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3 years ago
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The volume of a hemisphere with radius x is V(x) = 2/3 πx3. The volume of a cube with a height of x is shown in the graph. When
USPshnik [31]

Answer:hemisphere

Step-by-step explanation:

8 0
3 years ago
Find an equation of the sphere with center s23, 2, 5d and radius 4. What is the intersection of this sphere with the yz-plane?
spayn [35]

Answer:

Equation: (x+3)^2+(y-2)^2+(z-5)^2=16

Intersection: (y-2)^2+(z-5)^2=7

Step-by-step explanation:        

We are asked to write an equation of the sphere with center center (-3,2,5) and radius 4.    

We know that equation of a sphere with radius 'r' and center at (h,k,l) is in form:

(x-h)^2+(y-k)^2+(z-l)^2=r^2

Since center of the given sphere is at point (-3,2,5), so we will substitute h=-3, k=2, l=5 and r=4 in above equation as:

(x-(-3))^2+(y-2)^2+(z-5)^2=4^2

(x+3)^2+(y-2)^2+(z-5)^2=16

Therefore, our required equation would be (x+3)^2+(y-2)^2+(z-5)^2=16.

To find the intersection of our sphere with the yz-plane, we will substitute x=0 in our equation as:

(0+3)^2+(y-2)^2+(z-5)^2=16

9+(y-2)^2+(z-5)^2=16

9-9+(y-2)^2+(z-5)^2=16-9

(y-2)^2+(z-5)^2=7

Therefore, the intersection of the given sphere with the yz-plane would be (y-2)^2+(z-5)^2=7.

7 0
3 years ago
Please help me answer it​
jeka94

Answer:

i dont know toooo pls answer it fast......................................

Step-by-step explanation:

i need it..........................

3 0
3 years ago
What choice is it?? please help
Illusion [34]
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