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3 years ago

What is greatest common factor of 54ab and 54ab to the power of 2

Mathematics

1 answer:

jarptica [38.1K]3 years ago

5 0

Answer:

54ab

Step-by-step explanation:

the only two factors of 54ab^2 and 54ab is 1 and 54ab and the greatest of that would be 54ab.

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3 years ago

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3 years ago

WILL.MARK BRAINLEST. ( The length of a rectangular garden is 5m longer than its breadth .If its perimeter is 150 m,find the area

inessss [21]

Answer:

1400m^2

Step-by-step explanation:

Solution,

Let the breadth of the rectangle be x m, then the length of the rectangle will be x+5 m,

Now,

Perimeter of the rectangle=2(l+b)

150=2(x+5+x)

150=2(2x+5)

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I hope it helped U

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3 0

3 years ago

Read 2 more answers

John was visiting four cities that form a rectangle on a coordinate grid at A(0, 4), B(4, 2), C(1, -4) and D(-3, -2). What is th

allsm [11]

Answer:

$Area = 30$

Step-by-step explanation:

Given

Rectangle coordinates

$A = (0,4)$

$B = (4,2)$

$C = (1,-4)$

$D =(-3,-2)$

Required

The area of the rectangle

The area is calculated as:

$Area = Length* Width$

The length of the rectangle will be represented as:

$Length = AB = CD$

And the width is:

$Width = BC = AD$

Calculate distance AB using:

$AB = \sqrt{(x_1 - x_2)^2 +(y_1 - y_2)^2 }$

Where:

$A = (0,4)$ --- $(x_1,y_1)$

$B = (4,2)$ $--- (x_2,y_2)$

$AB = \sqrt{(0 - 4)^2 +(4 - 2)^2 }$

$AB = \sqrt{(- 4)^2 +(2)^2 }$

$AB = \sqrt{16 +4 }$

$AB = \sqrt{20}$

Calculate distance BC using:

$BC = \sqrt{(x_1 - x_2)^2 +(y_1 - y_2)^2 }$

$C = (1,-4)$ $---(x_1,y_1)$

$B = (4,2)$ $--- (x_2,y_2)$

$BC = \sqrt{(1 - 4)^2 +(-4 - 2)^2 }$

$BC = \sqrt{(- 3)^2 +(-6)^2 }$

$BC = \sqrt{9 +36}$

$BC = \sqrt{45}$

So, the area is:

$Area = Length * Width$

$Area = AB * BC$

$Area = \sqrt{20} * \sqrt{45}$

$Area = \sqrt{20 * 45}$

$Area = \sqrt{900$

$Area = 30$

4 0

3 years ago

What is greatest ﻿common ﻿factor ﻿of ﻿54ab and 54ab to the power of 2

What is greatest common factor of 54ab and 54ab to the power of 2