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3 years ago

PLZ HELP ASAP 20 POINTS

Mathematics

2 answers:

Sonbull [250]3 years ago

5 0

Answer:

a).no sugar=1. flour=3 1/2

B). sugar= 1 1/2. Flour= 5 1/4

c) your just simplifying to the smallest possible number

Step-by-step explanation:

1/2 doubled= 1 (1/2+1\2)

1 3/4= 7/4

7/4 doubled= 14/4=3 2/4= 3 1/2(1 1/3+1 1/3)

fomenos3 years ago

3 0

Ok so first lets do A. Her measurements are not correct the actual double is 1 cup of sugar and 3 1/2 cups of flour
Explanation:
2=2/1

Multiply 1/2 by 2/1 you get 1
Change 1 3/4 to an improper fraction and do the same
Multiply 7/4 by 2/1 you get 14/4 which equals 3 1/2

Now B. She would do the same thing but with three instead so

1/2x3/1= 3/2= 1 1/2
7/4x3/1= 21/4= 5 1/4

Now C the process for changing a mixed number into an improper fraction is you multiply the whole number by the denominator and add it to the numerator.

Brainliest my answer if this helped you?

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3 years ago

The oil prices for 2014, rounded to the nearest dollar, were: 95, 101, 101, 102, 102, 106, 104, 97, 93, 84, 76, 59. what is the

kipiarov [429]

Interquartile Range (IQR) = $Q_3-Q_1$ , with $Q_3$ as the upper quartile and $Q_1$ as the lower quartile.

Firstly, rearrange the data so that it's in ascending order: $\{59,76,84,93,95,97,101,101,102,102,104,106\}$

Next, find the median:

$\{59,76,84,93,95,\boxed{97,101,}101,102,102,104,106\}\\\\\frac{97+101}{2}\\\\\frac{198}{2}\\\\99$

Now to find the lower quartile, find the "median" of the data set that's to the left of 99:

$\{\overbrace{59,76,84,93,95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\{\overbrace{59,76,\boxed{84,93}95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\frac{84+93}{2}\\\\\frac{177}{2}\\\\88.5$

Now to find the upper quartile, it's the similar process as finding the lower quartile, except that you are finding the "median" of the data set to the right of 99:

$\{59,76,84,93,95,97,\overbrace{101,101,102,102,104,106}^{\textsf{to the right of the median}}\}\\\\\{59,76,84,93,95,97,\overbrace{101,101,\boxed{102,102} 104,106}^{\textsf{to the right of the median}}\}\\\\\frac{102+102}{2}\\\\\frac{204}{2}\\\\102$

Now that we have the upper and lower quartile, subtract them:

$102-88.5=13.5$

<u>In short, the IQR of this data set is 13.5.</u>

8 0

3 years ago

Write the equation in slope-intercept form and find the equation of a line through the given point (a) parallel and (b) perpendi

skelet666 [1.2K]

keeping in mind that parallel lines have the same exact slope, hmmm what's the slope of 4x - 2y = 3 anyway? well, let's put it in slope-intercept form firstly.

$\bf 4x-2y=3\implies 4x-3=2y\implies \cfrac{4x-3}{2}=y
\\\\\\
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so we're looking for a line whose slope is 2 and passes through 2,1.

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{1})~\hspace{10em}
slope = m\implies 2
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=2(x-2)
\\\\\\
y-1=2x-4\implies \blacktriangleright y=2x-3 \blacktriangleleft$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}}
{\stackrel{slope}{2\implies \cfrac{2}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{2}}}
\\\\[-0.35em]
\rule{34em}{0.25pt}$

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{1})~\hspace{10em}
slope = m\implies -\cfrac{1}{2}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=-\cfrac{1}{2}(x-2)
\\\\\\
y-1=-\cfrac{1}{2}x+1\implies \blacktriangleright y=-\cfrac{1}{2}x+2 \blacktriangleleft$

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3 years ago