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andre [41]
4 years ago
12

How much heat is released if 7.15 g cao(s) is added to 152 g of h2o(l)? cao(s) + h2o(l) → ca(oh)2(s) δh°rxn = –64.8 kj/mol?

Chemistry
1 answer:
aniked [119]4 years ago
6 0
First, we calculate the number of moles of each reactant using the formula:

Moles = mass / molecular weight

CaO:
Moles = 7.15/56 = 0.128 

Water:
Moles = 152/18 = 8.44

The reaction equation shows that the reactants must be present in an equal number of moles, so CaO will be the limiting reactant and 0.128 mole of calcium hydroxide will form.

The energy released is given by:

Heat of reaction * number of moles
= -64.8 * 0.128
= -8.29 kJ

8.29 kJ of energy will be released
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8 0
4 years ago
7 points
Free_Kalibri [48]

Answer: 12 ( answer not among the option)

Explanation:

From the equation of reaction; P4O10+ H2O     ----->    H3PO4, it is unbalanced.

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Adding '4' to H3PO4 on the RHS and '6' to H2O on LHS of the equation would give a balanced equation such as;

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6 0
3 years ago
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Hey there !:

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3 years ago
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