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stealth61 [152]
4 years ago
11

3. An irregularly shaped stone was lowered into a graduated cylinder holding a volume

Chemistry
1 answer:
omeli [17]4 years ago
6 0

Answer:

Hey there!

The volume rose by 5 ml, and that means the stone has a volume of 5 ml. Thus, the stone has a density of 25/5, or 5 g/cm^3.

Let  me know if this helps :)

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Antacids, such as Alka-Seltzer, use the reaction of sodium bicarbonate with citric acid in water solution to produce a fizz as f
Alex17521 [72]

Answer:

2.8248 g

Explanation:

First, consider the balanced chemical equation:

3NaHCO_{3} +C_{6}H_{8}O_{7} --->3CO_{2} +3H_{2}O +Na_{3}C_{6}H_{5}O_{7}\\

Then we calculate the number of moles in 4.11 g of citric acid:

n(citric acid)=\frac{4.11g}{192g/mol}=0.0214mol

According to the balanced reaction, one mole of citric acid produces 3 moles of carbon dioxide. That's 3 times the number f moles of citric acid. So we will do the same with the available number of moles of citric acid.

so n(carbon dioxide) = 0.0214 mol*3=0.0642 mol

mass(carbon dioxide)= mass*molar mass=0.0642 mol* 44g/mol

                                                                   = 2.8248 g

8 0
3 years ago
Which scientist is given credit for the plum pudding model of the atom
Ivanshal [37]

Ernest Rutherford is given credit for the plum pudding model of the atom. Hope this helps;)

8 0
4 years ago
Read 2 more answers
A balloon contains 3300 mL of helium gas at 63 °C. What is the final volume, in milliliters, of the gas when the temperature cha
Nesterboy [21]

The final volume : 3.4 L

<h3>Further explanation</h3>

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

V₁=3300 ml

T₁=63 + 273=336 K

T₂=78+273=351 K

the final volume :

\tt V_2=\dfrac{V_1.T_2}{T_1}\\\\V_2=\dfrac{3300\times 351}{336}\\\\V_2=3447.3~ml\rightarrow 2~sig.~fig.\rightarrow 3.4~L

8 0
3 years ago
Who developed the concept that the total pressure of a mixture of gases is the sum of their partial pressures?.
victus00 [196]

Answer:

John Dalton

Explanation:

John Dalton developed the concept tittle: Dalton Law of Partial Pressure.

The formula is: Pt = Pa + Pb + Pc...... Pn

3 0
2 years ago
Determine the location of the last significant place value by placing a bar over the digit.
Vlad1618 [11]

Answer:

8,040  

0.0300  

699.5  

2.000 x 102

0.90100  

90, 100  

4.7 x 10-8  

10,800,000.0  

3.01 x 1021

0.000410

Explanation:

First remember the following rules of determining the last significant place value :

1. The digits from 1-9 are all significant and zeros between significant digits are also significant.

2.  The trailing or ending zeroes are significant only in case of a decimal number otherwise they are ignored. However starting zeroes of such a number are not significant.

Now observing above rules, lets determine the location of the last significant place value of each given example. I am determining the location by turning the last significant place to bold.

1) 8,040

8,040

Location of the last significant place value is 3 and bar is over last significant digit that is 4. Number is not decimal so ending zero is ignored. Every non zero digit is a significant.

2)  0.0300

0.0300

Location is 3 and bar is over 0. Number has a decimal point so ending zero is not ignored but starting zeroes are ignored.

3) 699.5

699.5

Location is 4 and bar is over 5.

4) 2.000 x 10²

2.000 x 10²

Location is 4 and bar is over 0. This is because the number is decimal so trailing zeroes cannot be ignored. Also if we convert this number it becomes:

200.0 so last significant digit is 0 and location of last significant digit is 4.

5) 0.90100

0.90100

Location is 5 and bar is over 0. This is because in a number with decimal point starting zeroes are ignored but trailing zeroes after decimal point are not ignored. So we count from 9 and last significant digit is 0.

6) 90, 100

90, 100

Location is 3 and bar is over 1. This is because it is not a number with decimal point. So the trailing zeroes are ignored. The count starts from 9 and last significant is 1.

7) 4.7 x 10⁻⁸

4.7 x 10⁻⁸

Location is 2 and bar is over 7. This is because the starting zeroes in a number with a decimal point are ignored. So the first digit considered is 4 and last significant digit is 7. If we expand this number:

4.7 x 10⁻⁸ =    0.000000047 = 0.000000047

Here the starting zeroes are ignored because there is a decimal point in the number.

8) 10,800,000.0

10,800,000.0

Location is 9 and bar is over 0.  Number has a decimal point so ending zero is not ignored and last significant figure is 0.

However if the number is like:

10,800,000. Then location would be 8 and bar is over 0.

9) 3.01 x 10²¹

3.01 x 10²¹

Location is 3 and bar is over 1. Lets expand this number first

3.01 x 10²¹ = 3.01 x 1000000000000000000000

                  = 3010000000000000000000

So this is the number:

3010000000000000000000

Since this is number does not have a decimal point so the trailing zeroes are ignored. Hence the count starts from 3 and the last significant figure is 1

10) 0.000410

0.000410

Location is 3 and bar is over 0. This is because the number has a decimal point so the ending zero is not ignored but the starting zeroes are ignored according to the rules given above. Hence the first significant figure is 4 and last significant figure is 0.

6 0
3 years ago
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