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Nadusha1986 [10]
3 years ago
9

Do we generally break chemical bonds when we cool molecules?

Chemistry
1 answer:
olga_2 [115]3 years ago
7 0
The breaking of chemical bonds never releases energy to the external environment. Energy is only released when chemical bonds are formed. In general, a chemical reaction involves two steps: 1) the original chemical bonds between the atoms are broken, and 2) new bonds are formed. These two steps are sometimes lumped into one event for simplicity, but they are really two separate events. For instance, when you burn methane (natural gas) in your stove, the methane is reacting with oxygen to form carbon dioxide and water.
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Which is a positive effect of the technology advance of going from a compass to a gps
egoroff_w [7]

Answer:

Compass - Gps                              

Explanation:

I belive the pro's                                      and cons are

                                         GPS             you are trusting a little man made device

the direction you                               to give you directions

are going on                                        and that it won't break or die

a device not a paper map

                                                Compass

You can see north east south and              it is usually carefully crafted for                                                                                                                                                                          o                                                                     outdoors but it has no roads and

west on the compass and                          if given no directions, extremely

you can see the roads follow directions                  confusing until you learn it

like go south then east.

4 0
3 years ago
Both 1,2−dihydronaphthalene and 1,4−dihydronaphthalene may be selectively hydrogenated to 1,2,3,4−tetrahydronaphthalene. One of
pochemuha

Answer:

1,4-dihydro = 113 kJ·mol⁻¹

1,2-dihydro = 101 kJ·mol⁻¹

Explanation:

In 1,4-dihydronaphthalene, the 2,3-double bond is isolated from the benzene ring.

In 1,2-dihydronaphthalene, the 3,4-double bond is conjugated with the benzene ring.

Thus, 1,2-dihydronaphthalene is partially stabilized by resonance interactions between the ring and the double bond (think, styrene).

1,2-Dihydronaphthalene is at a lower energy level because of this stabilization.

The heat of hydrogenation of 1,2-dihydronaphthalene is therefore less than that of the 1,4-isomer when each is hydrogenated to the common product, 1,2,3,4-tetrahydronaphthalene.

8 0
2 years ago
The painkiller, Advil® contains the active ingredient ibuprofen (IB), which has a pKb of
denis23 [38]

This problem is providing the basic dissociation constant of ibuprofen (IB) as 5.20, its pH as 8.20 and is requiring the equilibrium concentration of the aforementioned drug by giving the chemical equation at equilibrium it takes place. The obtained result turned out to be D) 4.0 × 10−7 M, according to the following work:

First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:

Kb=\frac{[IBH^+][OH^-]}{[IB]}

Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:

pOH=14-8.20=5.80

[OH^-]=10^{-5.8}=1.585x10^{-6}M

Kb=10^{-5.20}=6.31x10^{-6}

Then, since the concentration of these ions equal that of the conjugated acid of the ibuprofen (IBH⁺), we can plug in these and the Kb to obtain:

6.31x10^{-6}=\frac{(1.585x10^{-6})(1.585x10^{-6})}{[IB]}

Finally, we solve for the equilibrium concentration of ibuprofen:

[IB]=\frac{(1.585x10^{-6})(1.585x10^{-6})}{6.31x10^{-6}}=4.0x10^{-7}

Learn more:

(Weak base equilibrium calculation) brainly.com/question/9426156

4 0
2 years ago
A reaction in the laboratory yields 5.98 g KAI(SO2)2, How many moles of potassium aluminum
Ivahew [28]

Answer:

0.0308 mol

Explanation:

In order to convert from grams of any given substance to moles, we need to use its molar mass:

  • Molar mass of KAI(SO₂)₂ = MM of K + MM of Al + (MM of S + 2*MM of O)*2
  • Molar mass of KAI(SO₂)₂ = 194 g/mol

Now we <u>calculate the number of moles of KAI(SO₂)₂ contained in 5.98 g</u>:

  • 5.98 g ÷ 194 g/mol = 0.0308 mol
6 0
2 years ago
Calculate the [oh−] in a solution with a ph of 12.52.
BaLLatris [955]
PH + pOH = 14

12.52 + pOH = 14

pOH = 14 - 12.52

pOH = 1.48

[OH⁻] = 10^ -pOH

[OH⁻] = 10 ^- 1.48

[OH⁻] = 0.033 M
6 0
3 years ago
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