9514 1404 393
Answer:
a) average rate = (total distance)/(total time)
b) Rave = 2·R1·R2/(R1 +R2)
c) cheetah's average rate ≈ 50.91 mph
Step-by-step explanation:
a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...
First leg distance: AB = 70·t1 ⇒ t1 = AB/70
Second leg distance: AB = 40·t2 ⇒ t2 = AB/40
The average rate is the ratio of total distance to total time:
average rate = (AB +AB)/(t1 +t2)
average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)
average rate = 560/11 = 50 10/11 . . . mph
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No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.
b) For two rates over the same distance (as above), the average is their harmonic mean:
average rate = 2r1·r2/(r1+r2)
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c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.
Answer:
The answer is she lost 9 matches
Step-by-step explanation:
The given question is incomplete. The complete question is:
Omar rented a truck for one day. There was a base fee of $17.95, and there was an additional charge of 98 cents for each mile driven. Omar had to pay $23 when he returned the truck. For how many mile did he drive the truck?
Answer: Omar drove the truck for 5.15 miles
Step-by-step explanation:
Base fee = 17.95 $
Additional charge per mile = 98 cents = 0.98 $ ( 100cents = 1$)
Now Omar payed = 22 $
Let the miles he travelled = x
Now , 
Solvimg for x :
Thus Omar drove the truck for 5.15 miles
Y-14=12# x+1 answer of math
Answer:
Step-by-step explanation:
3x+4y=29 .......(1)
6x+5y=43 .......(2)
Multiply equation (1) by 2
6x + 8y = 58......(3)
Substracting (2) from (3)
8y - 5y = 58 - 43
3y = 15
Dividing by 3
3y/3 = 15/3
y = 5
Substituting y = 5 into (2)
6x+5y=43
6x + 5(5) = 43
6x + 25 = 43
6x = 43 - 25
6x = 18
Dividing by 6
6x/6 = 18/6
x = 3
