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3 years ago

PLEASE HELP!! What is the standard deviation of a data set whose values are all the same?

Mathematics

2 answers:

amm18123 years ago

7 0

Recall that the formula for standard deviation of a sample is:
s
=
√
∑
n
i
=
1
(
x
i
−
¯
x
)
2
n
−
1

DaniilM [7]3 years ago

5 0

Answer:

zero

Step-by-step explanation:

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What are three different complex fractions that simplify to 1/4

GaryK [48]

I know one of them is 1/2

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3 years ago

How do I solve 3+k/14=4

Sedaia [141]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{k = 53}}}}}$

Step-by-step explanation:

$\bigstar{ \sf{ \: \: \frac{3 + k}{14} = 4}}$

$\tt{Step \: 1 \: }$ : Do cross multiplication

$\hookrightarrow{ \sf{3 + k = 4 \times 14}}$

$\tt{Step \: 2}$ : Multiply the numbers : 4 and 14

$\hookrightarrow{ \sf{3 + k = 56}}$

$\tt{Step \: 3 \: }$ Move 3 to right hand side and change it's sign

$\hookrightarrow{ \sf{k = 56 - 3}}$

$\tt{Step \: 4 \: }$ Subtract 3 from 56

$\hookrightarrow{ \sf{k = 53}}$

The value of k is 53

Hope I helped!

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~TheAnimeGirl

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3 years ago

Read 2 more answers

PLEADSE HELP ILL GIVE BARINLIESDT

Vlada [557]

Answer:

non-proportional's with positive y intercept are:

y=2.5x-7

y=-5x-8

proportional's with positive y intercept are:

y=1.2x

y=-10x

y=7x/8+1

7 0

2 years ago

How to differentiate ?

Bas_tet [7]

Use the power, product, and chain rules:

$y = x^2 (3x-1)^3$

• product rule

$\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d(x^2)}{\mathrm dx}\times(3x-1)^3 + x^2\times\dfrac{\mathrm d(3x-1)^3}{\mathrm dx}$

• power rule for the first term, and power/chain rules for the second term:

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(x-1)^2\times\dfrac{\mathrm d(3x-1)}{\mathrm dx}$

• power rule

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(3x-1)^2\times3$

Now simplify.

$\dfrac{\mathrm dy}{\mathrm dx} = 2x(3x-1)^3 + 9x^2(3x-1)^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2 \times (2(3x-1) + 9x) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2(15x-2)}$

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.

On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

$\ln(y) = \ln\left(x^2(3x-1)^3\right) \\\\ \ln(y) = \ln\left(x^2\right) + \ln\left((3x-1)^3\right) \\\\ \ln(y) = 2\ln(x) + 3\ln(3x-1)$

Differentiate both sides and you end up with the same derivative:

$\dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac2x + \dfrac9{3x-1} \\\\ \dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \times x^2(3x-1)^3 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(15x-2)(3x-1)^2$

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2 years ago

A mountain gorilla weighs 135 pounds and is gaining pound each week. An eastern gorilla

Tju [1.3M]

Answer:

njnnnnnnn

Step-by-step explanation:

nmkm

6 0

3 years ago