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2 years ago

"Yo no sé cuál fue la razón Si yo te estaba dando todo mi amor."

Mathematics

2 answers:

stiv31 [10]2 years ago

6 0

oh tan dulce de tu parte........

Charra [1.4K]2 years ago

3 0

que otra vez tu ???

$\: \: \:$

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SinA=√1-x÷√1+X<br> Find the value of cosA

Irina-Kira [14]

The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = $\sqrt{1} - x$

Hypotenuse = $\sqrt{1} + x$

Let's find the adjacent side using the Pythagorean theroem

$(\sqrt{1} + x)^2 = (\sqrt{1 -x } )^2 + x^2$

$1 + x^2 = 1 - x^2 + x^2$

$x = \sqrt{\frac{1 + x^2}{1 -x^2} }$

cos A = x/hypotenuse

$cos A = \frac{\sqrt{\frac{1+x^2}{1 -x^2} } }{\sqrt{1} +x}$

cos A = √(1 + x²)/ (1 - x²) /√1 + x

Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

Learn more about trigonometric identities here:

brainly.com/question/7331447

#SPJ1

6 0

1 year ago

A brick layer is hired to build three walls

hjlf

Answer is B because brick starts with a B

8 0

2 years ago

PLEASE HELP

lilavasa [31]

Those two functions just miss each other so there are no real solutions. Every polynomial with complex coefficients has complex solutions.

$2x^2 + 2 = 3x$

$2x^2 - 3x = -2$

$2( x^2 - \frac 3 2 x) = -2$

$x^2 - \frac 3 2 x = -1$

$x^2- \frac 3 2 x+ (\frac 3 4)^2= -1 + (\frac 3 4 )^2$

$(x - \frac 3 4)^2 = -\frac 7{16}$

$x - \frac 3 4 = \pm \sqrt{ -\frac 7{16}}$

$x = \frac 3 4 \pm \frac i 4 \sqrt{7}$

$x = \frac 1 4(3 \pm i \sqrt{7})$

4 0

2 years ago

Katy has 46 missing assignments in math class and 60 missing assignments in history. She has 106 missing assignments in total. K

guapka [62]

Answer:

She needs to do at least 8 a day

Step-by-step explanation:

4 0

2 years ago

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SADFHUABSUDHAYSDXNINWYGBXIDNYW PLEASE ANSEWR

Alenkinab [10]

Answer:

$15x-6y=48$

Step-by-step explanation:

So we have the system of equations:

$5x-2y=16\\15x-7y=51$

And we want to multiply the first equation by some constant such that the resulting equation matches the coefficient of [x] in the second equation.

We can see that the coefficient of x in the second equation is 15.

So, to match 15, we must multiply the first equation by 3. So:

$3(5x-2y)=3(16)$

Multiply:

$15x-6y=48$

And we're done!

5 0

2 years ago

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