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3 years ago

Which of these is not a characteristic of a perpendicular bisector?

Mathematics

2 answers:

Dvinal [7]3 years ago

8 0

Answer:

the perpendicular bisector meets any line at an angle which is not 90°

Arte-miy333 [17]3 years ago

7 0

Answer:

The perpendicular bisector meets any line at an angle which is not 90°

Step-by-step explanation:

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In a certain city the temperature in degrees Fahrenheit t hours after 9 am was approximated by the function T(t) = 50 + 13 sin (

Liula [17]

Answer:

The average temperature during the period of 9 am to 9 pm is 58.276 ° F

Step-by-step explanation:

From the given information, the time given as 9 pm implies that t = 12, since there is a period of 12 hours between 9 am to 9 pm.

Hence,

Let the average temperature be represented with $T_{avg}$

Then:

$T_{avg} = \dfrac{1}{12-0}\int^{12}_{0} T(t) dt$

$T_{avg} = \dfrac{1}{12}\int^{12}_{0} (50+13 \ sin ( \dfrac{\pi t}{12}))dt$

$T_{avg} = \dfrac{1}{12} \begin {bmatrix} 50t + 13 \begin {pmatrix} -\dfrac{cos \dfrac{\pi t}{12} }{\dfrac{\pi}{12}} \end {pmatrix} \end {bmatrix}^{12}_{0}$

$T_{avg} = \dfrac{1}{12} \begin {bmatrix} 50t - \dfrac{13(12)}{\pi} \ cos \begin {pmatrix} \dfrac{\pi t}{12} \end {pmatrix} \end {bmatrix}^{12}_{0}$

$T_{avg} = \dfrac{1}{12} \begin {bmatrix} 50(12) - \dfrac{13(12)}{\pi} \ cos \begin {pmatrix} \dfrac{\pi (12)}{12}\end {pmatrix} - 50 (0) + \dfrac{13(12)}{\pi} cos \begin{pmatrix}\dfrac{\pi (0)}{12} \end {pmatrix} \end {bmatrix}$

$T_{avg} = \dfrac{1}{12} \begin {bmatrix} 50(12) - \dfrac{156}{\pi} \ cos \pi - 50 (0) + \dfrac{156}{\pi} cos (0) \end {bmatrix}$

$T_{avg} = \dfrac{1}{12} \begin {bmatrix} 50(12) - \dfrac{156}{\pi} (-1)- 50 (0) + \dfrac{156}{\pi} (1) \end {bmatrix}$

$T_{avg} = \dfrac{1}{12} \begin {bmatrix} 600 + \dfrac{156}{\pi} + \dfrac{156}{\pi} \end {bmatrix}$

$T_{avg} = \dfrac{1}{12} \begin {bmatrix} 600 + \dfrac{312}{\pi} \end {bmatrix}$

$T_{avg} = \dfrac{1}{12} \begin {bmatrix} 699.3126845 \end {bmatrix}$

$\mathbf{T_{avg} = 58.276}$

Therefore, the average temperature during the period of 9 am to 9 pm is 58.276 ° F

5 0

3 years ago

50 POINTS AND BRAINLIESTIF I CAN thank you

miv72 [106K]

Answer/Step-by-step explanation:

Let's use Pythagorean theorem:

Formula : a² + b² = c²

Note that:

a is the long leg of the triangle

b is the short leg of the triangle

c is the hypotenuse

Side lengths Given are; 3 inches, 4 inches, 5 inches of a right triangle.

Hence,

a = 4 inches

b = 3 inches

c = 5 inches

Thus,

4² + 3² = 5²

16 + 9 = 25

25 = 25 [True]

[RevyBreeze]

8 0

3 years ago

Read 2 more answers

00458 in scientific notation

ludmilkaskok [199]

The answer is: " 4.58 * 10⁻² " .
_____________________________________________________

7 0

4 years ago

Please help! it's algebra 2! correct answers only!

Paul [167]

To create a square trinomial on the left side of the equation, find a value that is equal to the square of half of.

4 0

3 years ago

It takes printer A 4 more minutes than printer B to print 40 pages. If working together, the two printers can print 50 pages in

Anastaziya [24]

Answer:

It will take printer A 24 minutes to print 80 pages.

Step-by-step explanation:

It takes printer A 4 more minutes than printer B to print 40 pages.

Let the time it takes printer B be x minutes, since printer A prints at 4 minutes more, it prints at (x + 4) minutes.

Printer A prints at the rate of (40/(x+4)) pages per minute.

Printer B prints at the rate of (40/x) pages per minute.

If working together, the two printers can print 50 pages in 6 minutes

They can print at the rate of 50 pages per 6 minutes, if working together.

Let us add these ratios, the

40/(x + 4) + 40/x = 50/6

Divide by 40

1/(x + 4) + 1/x = 5/24

(x + x + 4)/x(x + 4) = 5/24

2x + 4 = (5/24)(x² + 4x)

48x + 96 = 5x² + 20x

5x² - 28x - 96 = 0

Solving this using the quadratic formula,

x = [-b ± √(b² - 4ac)]/2a

a = 5, b = -28, and c = -96

x = [28 ± √(784 + 1920)]/10

= 28/10 ± √(2704)/10

= 28/10 ± 52/10

x = (28+52)/10 = 80/10 = 8

x = (28 - 52)/10 = -24/10 = -2.4

So, x is either 8 or -2.4

Since we are dealing with time, the realistic value is the positive value, x = 8, then we choose x = 8 minutes.