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Sever21 [200]
2 years ago
9

Which of these is not a characteristic of a perpendicular bisector?

Mathematics
2 answers:
Dvinal [7]2 years ago
8 0

Answer:

the perpendicular bisector meets any line at an angle which is not 90°

Arte-miy333 [17]2 years ago
7 0

Answer:

The perpendicular bisector meets any line at an angle which is not 90°

Step-by-step explanation:

.

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All of the following are correct except _____. 3 2 + 5 - 2 = 12 3 2 - 5 + 2 = 6 3 2 5 + 2 = 47 3 2 + 5 2 = 28
zepelin [54]

Answer:

269

Step-by-step explanation:

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3 years ago
What is the slope of the line that passes through (-2, 7) and (4, 9)?
prohojiy [21]
Slope=(9-7)/(4+ 2) = 1/3
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Find the side of a square whose diagonal is of the given measure.<br> Given = 15.2 cm
Neko [114]

Answer:

15cm

Step-by-step explanation:

First, a square's diagonal is basically the hypotenuse of a 45-45-90 triangle. a 45-45-90 triangle has a really special relationship, where the side length is x, and the diagonal is x \sqrt{2}. So, the side length is 15.

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What's the distance between (1,7) and (-2,-4)
Lynna [10]

Answer:

Finite Math Examples. Popular Problems · Finite Math. Find the Distance Between Two Points (7,2) , (-1,4).

Step-by-step explanation:

Finite Math Examples. Popular Problems · Finite Math. Find the Distance Between Two Points (7,2) , (-1,4).

8 0
2 years ago
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What is the range of the function below in set builder notation? y=|x-3|
Kisachek [45]

Answer:  \{y | \ y \in \mathbb{R}, \ y \ge 0\}

This translates to "y is any real number such that it is 0 or larger".

The reasoning is that the result of any absolute value function is either 0 or positive. In other words, we'll never get a negative result of an absolute value function. This is due to how absolute value represents distance. Negative distance does not make sense.

So if y = |x-3| then y = 0 is the smallest output possible. We could have any positive output we want.

In terms of a graph (see below), the V shape is at the lowest point (3,0). The y coordinate is all we care about in terms of finding the range. So we see the lowest y value is y = 0.

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3 years ago
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