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vovangra [49]
3 years ago
13

Replace with <,>, or = to make a true statement: 2^5 4^2

Mathematics
1 answer:
Crank3 years ago
3 0

Answer:

2^5>4^2

Step-by-step explanation:

{2}^{5}  >  {4}^{2}  \\ 32 > 16

hopefully this makes sense

:)

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Question 7<br> Solve the Equation:<br> D(7) = ?<br> D= 8
Degger [83]
If 8=8 it will be 8(7) which means we have to do 8*7 and 8*7 will be 56 so the answer is 56 :) brainliest would be appreciated
4 0
3 years ago
the length of a rectangle is 9 centimeters more than the width. the area is 112 square centimeters. find the length and width of
NeX [460]
Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)







8 0
4 years ago
Read 2 more answers
Please answer quickly I only have 5 mins lol. The ratio of students polled in 6th grade who prefer lemonade to Iced tea is 8:4,
zhannawk [14.2K]

Answer:

Let total students who prefer lemonade is 2a and who prefer ice tea is a.

Students in 6th grade=39

2a+a=39

3a=39

a=39/3

a=13

students who prefer lemonate is 13

and those who prefer ice tea is 2a=26

4 0
3 years ago
What is the exact circumference of the circle?
fredd [130]
Data:

Formula: diameter = 2*radius

Formula: (<span>Circle length)
</span>C = 2* \pi *r
<span>
Solving: </span><span>Using the data
</span>diameter = 2*radius
20 = 2*r
2r = 20
r =  \frac{20}{2}
\boxed{r = 10\:ft}

<span>Now, replace in the circumference length formula
</span>C = 2 \pi *r
C = 2 \pi *10
\boxed{\boxed{C = 20 \pi \:ft}}\end{array}}\qquad\quad\checkmark

Answer:
<span>The exact circumference of the circle is </span>20 \pi \:ft
7 0
3 years ago
A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2​, drawn from the 11​, will
svet-max [94.6K]

The required probability is \frac{36}{55}

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.  

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, \text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}

Probability for first draw to be non-defective =\frac{11-2}{11}=\frac{9}{11}

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective =\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}

(printers after first slot = 10; total defective printers = 2)

Then, total probability =\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}

7 0
4 years ago
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