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3 years ago

13

Replace with <,>, or = to make a true statement: 2^5 4^2

1 answer:

Crank3 years ago

3 0

Answer:

2^5>4^2

Step-by-step explanation:

${2}^{5} > {4}^{2} \\ 32 > 16$

hopefully this makes sense

:)

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Mariel went to Macy's .she bought a coat for159.90.mariel presented the casher with a coupon that was 25 percent off .Calculate

weeeeeb [17]

Answer: Discount = $39.98

Step-by-step explanation:

Given coupon discount of 25% off

Discount will be 25% of cost of the coat

Cost of the coat = $159.90

Discount = 25/100 × 159.90

= $39.975

Approximately $39.98

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3 years ago

What is 6.25 as a fraction and percent

ipn [44]

Convert the decimal by multiplying by 100.<span>625<span>%
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3 years ago

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PLEASE HELP !! ILL GIVE BRAINLIEST !!

Leni [432]

Answer:

<HIK to <GFD

Step-by-step explanation:

Alternate exterior angles are angles that are on the exterior sides alternately on a transversal

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3 years ago

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How can I do this I'm so stuck on this plz help

Stolb23 [73]

You're just changing the given rate into a unit rate: follow along and do the division shown and fill in the blanks. 320 ÷16 = 20

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3 years ago

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Learning Task 3:

padilas [110]

Answer:

$Area = x^2- 25$

$Area =9x^2 +24x + 16$

$Length = (3x -2)$

$Speed = \left(y^2-3y+1\right)$

$Product = 3m^3 + 6m^2 - 6m$

Step-by-step explanation:

Solving (1):

$Length = (x + 5)$

$Width = (x - 5)$

Required

Calculate Area

$Area = Length * Width$

$Area = (x + 5) * (x - 5)$

$Area = x^2 + 5x - 5x - 25$

$Area = x^2- 25$

Solving (2):

Given

$Length = (3x + 4)$

Required: Calculate Area

$Area =Length * Length$

$Area =(3x + 4) * (3x + 4)$

$Area =9x^2 + 12x + 12x + 16$

$Area =9x^2 +24x + 16$

Solving (3):

$Area = 3x^2 + 7x - 6$

$Width = x + 3$

Required: Calculate Length

$Area = Length * Width$

$Length = \frac{Area}{Width}$

$Length = \frac{3x^2 + 7x - 6}{x + 3}$

Factorize the numerator

$Length = \frac{3x^2 + 9x -2x - 6}{x + 3}$

$Length = \frac{3x(x + 3) -2(x + 3)}{x + 3}$

$Length = \frac{(3x -2) (x + 3)}{x + 3}$

Divide by x + 3

$Length = (3x -2)$

Solving (4):

$Distance = (2y^3 - 7y^2 + 5y -1)$

$Time = 2y - 1$

Required: Determine the average speed

This is calculated as:

$Speed = \frac{Distance}{Time}$

$Speed = \frac{2y^3 - 7y^2 + 5y -1}{2y - 1}$

Factorize the numerator

$Speed = \frac{\left(2y-1\right)\left(y^2-3y+1\right)}{2y - 1}$

$Speed = \left(y^2-3y+1\right)$

Solving (5):

Multiply $(m^2 + 2m - 2)$ by sum of $(m + 3)$ and $(2m - 3)$

First, calculate the sum:

$Sum = m + 3 + 2m - 3$

$Sum = m + 2m+3 - 3$

$Sum = 3m$

Then, the product

$Product = (m^2 + 2m - 2)(3m)$

$Product = 3m^3 + 6m^2 - 6m$

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3 years ago

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