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PolarNik [594]
2 years ago
11

In the year 2000, the population of a city was 600,000 citizens. The population increases at a rate of 1.8% per year.

Mathematics
2 answers:
creativ13 [48]2 years ago
7 0

SOS

Answer:

a) 600,000 (1.018)ᵗ, the graph is below:

* "t" is the years. 2000 is the first year, so "t" would be 1. 2012 is the 12th year so "t" would be 12.

b) As the years go by, the population increases. The years (X), and population (Y) both increase together. The graph shows that when the years increase the population increases.

c) In 2012, which would be 12 years later, I predict the population would be around 743,232 people.



Alona [7]2 years ago
6 0
Y=600000(1+1.8%)^(x-2000)
So the population in 2012
Y=600,000×(1+0.018)^(2,012−2,000)
Y=743,232
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You are at a European beach with 60 other visitors. 36 of them speak English. If you randomly meet two people on the beach, what
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I assume I remember that first person; so I remove him from the marbles (by avoiding him on the beach) and now my probability is p(E and E) = n(E)/N * n(E)-1/(N - 1) = 35/59*34/58 = 0.347749854 ANS

Following the same logic p(E and E and E) = 35/59*34/58*33/57 = 0.201328863 ANS

This last one is different from the first three.  This one is p(E >= 1|4 attempts).  We can trace out a probability tree to identify those branches that contain at least one E event.  So:

EEEE p() = 35/59 * 34/58 * 33/57 * 32/56 =  

EEES p() = 35/59 * 34/58 * 33/57 * 24/56 =

EESE p() = 35/59 * 34/58 * 24/57 * 33/56 =

ESEE p() = 35/59 * 24/58 * 34/57 * 33/56 =

SEEE p() = 24/59 * 35/58 * 34/57 * 33/56 =

EESS p() = 35/59 * 34/58 * 24/57 * 23/56 =

ESES p() = 35/59 * 24/58 * 34/57 * 23/56 =

SEES

SESE

SSEE

ESSS  And so on, but...a big BUT...why do all this when

SESS

SSES

SSSE

SSSS

p(E>=1|4) = 1 - p(S and S and S and S) = 1 - 24/59 * 23/58 * 22/57 * 21/56 = 0.976652619   ANS.  In other words we find the probability of not meeting an Englishman and take 1 minus that value to find the probability of meeting at least one.

00

Step-by-step explanation:

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