um I dunno because I need points to ask a question sorry
Answer:
Nope
Step-by-step explanation:
To now if a triangle is a right angle, use Pythagoras Theorem,
a^2 + b^2 = c^2
C usually be the longest side of the triangle, C = 17
Then also let a and b be 6 and 13 respectively.
6^2 + 13^2 =205
C^2 = 205
C = sqrt(205) = 14.32
therefore no this is not a right angle triangle
Answer:
if sin (x-3) degrees = cos (2x+6) degrees, find the value of x.
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Note: sin and cos are complementary functions....
sin(x) = cos (90-x)
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Your Problem:
sin(x-3) = cos(90-(x-3))
Equation:
90-[x-3] = 2x+6
90-x+3 = 2x+6
3x = 93-6
x = 31-2
x = 29
Step-by-step explanation:
Try this solution:
1. m∠A=m∠L; m∠B=m∠M and m∠C=m∠N;
2. m∠B=m∠M=35° and m∠C=m∠N=95°;
3. m∠A=m∠L=180°-(m∠B+m∠C)=180-35-95=50°
answer: 50°
X= 105
explanation:
45+30=75
180-75= 105
