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Svetllana [295]
2 years ago
12

Please help me with this!

Mathematics
1 answer:
GREYUIT [131]2 years ago
5 0

Answer:

p=-7

Step-by-step explanation:

-11+10(p+10)=4-5(2p+11)

Firstly, expand the bracket

-11+10p+100=4-10p-55

Next, you collect like terms

10p+10p=4-55-100+11

20p=-140

Divide through by the coefficient of p

20p/20=-140/20

p=-7

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ruffles classic + those two bite cupcakes literally best thing to exist

Step-by-step explanation:

7 0
3 years ago
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PLEASE HELP ASAP FOR 10 POINTS
Olenka [21]

Answer:

The answer is 4m

Step-by-step explanation:

5 0
3 years ago
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Kai wrote the number 85 on the board. Is 85 a prime or composite?
Lesechka [4]
85 is not a prime, it’s a composite number.
7 0
3 years ago
What is this area? please help
Gnoma [55]

Answer:

60

Step-by-step explanation:

multiply the 20m x 6m

20x6=120. Is base x high

then

divide ➗ by 2

is equal to 60

I hope help you

4 0
3 years ago
How do you solve this equation?
Travka [436]
Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero

5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1


5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4







second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
2^x=8
x=3

2^x-2=0
2^x=2
x=1

x=3 or 1







first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3


7 0
3 years ago
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