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2 years ago

Please help me with this!

Mathematics

1 answer:

GREYUIT [131]2 years ago

5 0

Answer:

p=-7

Step-by-step explanation:

-11+10(p+10)=4-5(2p+11)

Firstly, expand the bracket

-11+10p+100=4-10p-55

Next, you collect like terms

10p+10p=4-55-100+11

20p=-140

Divide through by the coefficient of p

20p/20=-140/20

p=-7

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Kirk's family drove 36 miles in 50 minutes, which was 48% of the distance to his grandmother's house. What was the total distanc

Makovka662 [10]

Answer:

Option D is correct.

75 miles is the total distance in miles to Kirk's grandmother's house

Step-by-step explanation:

Let x represents the total distance in miles to Kirk's grandmother's house.

As per the statement:

Kirk's family drove 36 miles in 50 minutes, which was 48% of the distance to his grandmother's house

⇒ Distance Kirk's family drove = 36 miles.

then;

36 = 48% of x

$36 = \frac{48}{100}x$

Multiply both sides by 100 we get;

3600 = 48x

Divide both sides by 48 we have;

75 miles = x

Therefore, the total distance in miles to Kirk's grandmother's house is 75 miles

4 0

3 years ago

Read 2 more answers

The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep

Alchen [17]

Ooh, fun

geometric sequences can be represented as
$a_n=a(r)^{n-1}$
so the first 3 terms are
$a_1=a$
$a_2=a(r)$
$a_2=a(r)^2$

the sum is -7/10
$\frac{-7}{10}=a+ar+ar^2$
and their product is -1/125
$\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3$

from the 2nd equation we can take the cube root of both sides to get
$\frac{-1}{5}=ar$
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
$\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r$
subsituting -1/5 for ar
$\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r$
which simplifies to
$\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}$
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for $ax^2+bx+c=0$
$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$
so
for 2r²-5r+2=0
a=2
b=-5
c=2

$r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}$
$r=\frac{5 \pm \sqrt{25-16}}{4}$
$r=\frac{5 \pm \sqrt{9}}{4}$
$r=\frac{5 \pm 3}{4}$
so
$r=\frac{5+3}{4}=\frac{8}{4}=2$ or $r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

use them to solve for the value of a
$\frac{-1}{5}=ar$
$\frac{-1}{5r}=a$
try for r=2 and 1/2
$a=\frac{-1}{10}$ or $a=\frac{-2}{5}$

test each
for a=-1/10 and r=2
a+ar+ar²= $\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}$
it works

for a=-2/5 and r=1/2
a+ar+ar²= $\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}$
it works

both have the same terms but one is simplified

the 3 numbers are $\frac{-2}{5}$ , $\frac{-1}{5}$ , and $\frac{-1}{10}$

6 0

3 years ago

Find the equation of the

kolbaska11 [484]

Answer:

y=-1/3 x +2/3

Step-by-step explanation:

all steps are in picture